Question

 <-- 401 Unauthorized http://172.20.20.128/api/v1/login (126ms)
    D/OkHttp: Date: Tue, 19 Sep 2017 12:55:29 GMT
    D/OkHttp: Server: Apache/2.4.12 (Unix) OpenSSL/1.0.1m PHP/5.5.24 mod_perl/2.0.8-dev Perl/v5.16.3
    D/OkHttp: X-Powered-By: PHP/5.5.24
    D/OkHttp: Set-Cookie: PHPSESSID=bl0brh2n6pr1sbp76kf95q8um1; path=/; HttpOnly
    D/OkHttp: Expires: Thu, 19 Nov 1981 08:52:00 GMT
    D/OkHttp: Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0
    D/OkHttp: Pragma: no-cache
    D/OkHttp: Set-Cookie: language=26fb26f386223e2e177900bfa422048f6e2e5367s%3A5%3A%22en_us%22%3B; expires=Thu, 28-Dec-2017 12:55:29 GMT; Max-Age=8640000; path=/
    D/OkHttp: Content-Length: 68
    D/OkHttp: Keep-Alive: timeout=5, max=100
    D/OkHttp: Connection: Keep-Alive
    D/OkHttp: Content-Type: application/json
    D/OkHttp: {"error":true,"code":"401","message":"Invalid username or password"}
    D/OkHttp: 
    <-- END HTTP (68-byte body)

以上是在android监视器中显示的日志。我想获得上面的日志详细信息中显示的以下消息。

{"error":true,"code":"401","message":"Invalid username or password"}

这是我的请求

  call.validateUser(request)
            .subscribeOn(Schedulers.io())
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe(new Subscriber<Response<LoginResponse>>() {
                @Override
                public void onCompleted() {
                    AppLog.info("onCompleted", "onCompleted");
                }

                @Override
                public void onError(Throwable e) {
                    AppLog.info("onError", new Gson().toJson(e));// not coming to onError. 
                }

                @Override
                public void onNext(Response<LoginResponse> loginResponse) {

                    AppLog.info("code", "" + loginResponse.code()); // returns 401
                    AppLog.info("message", loginResponse.message()); // returns Unauthorized
                    LoginResponse response = loginResponse.body(); // returns null
                    AppLog.info("errorBody", new Gson().toJson(loginResponse.errorBody()));// returns null
                    AppLog.info("headers", new Gson().toJson(loginResponse.headers()));// returns header detail
                    AppLog.info("body", new Gson().toJson(loginResponse.body()));// returns null


                }
            });

我检查了onError回调。它还显示401 Unauthorized消息而不是原始错误消息。

Answer 1

为什么不能尝试onSucess（）; onRespose（）; onFailure处（）;所以coud会给出无效的用户名或密码错误

{{1}}

Answer 2

转到LoginResponse.java页面并编写我在此处写的代码

if

编写完此代码后，在api响应中编写以下代码

    @SerializedName("message")
public String message;

public String getmessage(){return message;}

@SerializedName("code")
public String code;

public String getcode(){return code;}

@SerializedName("error")
public String error;

public String geterror(){return error;}

Answer 3

尝试Interceptor，如图所示

compile 'com.squareup.okhttp3:logging-interceptor:x.x.x'

在RestClient类中添加以下内容

private APIInterface service;

public RestClient() {
        HttpLoggingInterceptor logging = new HttpLoggingInterceptor();
        logging.setLevel(HttpLoggingInterceptor.Level.BODY);
        OkHttpClient.Builder httpClient = new OkHttpClient.Builder();

        httpClient.addInterceptor(logging);
        Retrofit retrofit = new Retrofit.Builder()
                .baseUrl(AppConfiguration.BASEURL)
                .addConverterFactory(GsonConverterFactory.create())
                .client(httpClient.build())
                .build();
        service = retrofit.create(APIInterface.class);
    }

查看this 了解详情

Answer 4

你有Observable<Response<LoginResponse>>。

从https://github.com/square/retrofit/issues/1218

引用jake

构建您的observable有三种方法：

1. Observable<BodyType>
2. Observable<Response<BodyType>>
3. Observable<Result<BodyType>>

对于第一个版本，无法挂起非200响应信息，因此它包含在传递给onError的异常中。对于后两者，数据被封装在Response对象中可以通过调用errorBody（）来访问。

您可以使用https://square.github.io/retrofit/2.x/retrofit/retrofit2/Response.html#errorBody--

中的loginResponse.errorBody()

您可以登录onNext

if(loginResponse.isSuccessfull() {

     // do something
} else {

 AppLog.info("errorbody",listResponse.errorBody().string());

}

注意：在回答之前，我尝试了一个返回404状态代码的示例api。 new Gson().toJson(loginResponse.body())确实返回null。我改为loginResponse.errorBody().string()，我能够记录错误正文

如何在android中获取Retrofit错误消息？

4 个答案: