Question

我正在尝试构建一个ArrayAdapter，允许用户访问链接到互联网，googlemaps等的各个TextView字段。我无法解决错误状态的问题

无法解析方法'startActivity（android.content.Intent）。

在这里查看了很多帖子之后，我已经确定这是context的问题，我不知道如何从下面的代码中得到这个。任何帮助将不胜感激：）

package com.example.stuart.listitemviewtest;
import android.content.Context;
import android.content.Intent;
import android.net.Uri;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.TextView;
import java.util.ArrayList;
import java.util.List;


public class AttractionAdapter extends ArrayAdapter {
     public AttractionAdapter(Context context, ArrayList<Attraction> attractions) {
    super(context, 0, attractions);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
    // Check if the existing view is being reused, otherwise inflate the view
    View listItemView = convertView;
    if(listItemView == null) {
        listItemView = LayoutInflater.from(getContext()).inflate(
                R.layout.list_item, parent, false);
    }
    // Get the {@link currentAttraction} object located at this position in the list
    final Attraction currentAttraction = (Attraction) getItem(position);

    final TextView attractionName = (TextView) listItemView.findViewById(R.id.attraction_name);
    attractionName.setText(currentAttraction.getmName());
    attractionName.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            Log.i("attraction Name", "the name of attraction: " + currentAttraction.getmName());
        }
    });
    TextView attractionURL =(TextView) listItemView.findViewById(R.id.attraction_URL);
    attractionURL.setText(currentAttraction.getmWebAddress());
    attractionURL.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {

    //get web address
    Log.i("Web Address", "The web address is: " +                           currentAttraction.getmWebAddress());


        //load URL in new window
          Intent intent = new Intent();
             intent.setAction(Intent.ACTION_VIEW);
             intent.addCategory(Intent.CATEGORY_BROWSABLE);
             intent.setData(Uri.parse(currentAttraction.getmWebAddress()));
             startActivity(intent);
        }
    });
    return listItemView;
}
}

Answer 1

像这样更改构造函数： -

  Context mContext;
  public AttractionAdapter(Context context, ArrayList<Attraction> attractions) {
super(context, 0, attractions);
mContext = context;
}

现在在startActivity（）;

之前使用mContext

   Intent intent = new Intent();
         intent.setAction(Intent.ACTION_VIEW);
         intent.addCategory(Intent.CATEGORY_BROWSABLE);
         intent.setData(Uri.parse(currentAttraction.getmWebAddress()));
         mContext.startActivity(intent);

Answer 2

您需要一个上下文来启动一个新活动，即活动上下文

 //load URL in new window
 Intent intent = new Intent();
 intent.setAction(Intent.ACTION_VIEW);
 intent.addCategory(Intent.CATEGORY_BROWSABLE);
 intent.setData(Uri.parse(currentAttraction.getmWebAddress()));
 (listItemView.getContext()).startActivity(intent);

customAdapter中的onClick侦听器和上下文问题

2 个答案: