Question

我正在尝试Django中的文件上载 - 我在保存带有文件字段的表单方面遇到了问题。我对此有类似的看法，工作得非常好，我不明白为什么会在这个问题上引发错误。

from django.conf import settings
from django.core.files.storage import FileSystemStorage

def view1(request):
    ...
    if form.is_valid():
        form.save()
        ...

然后在我的models.py

中

def upload_path(var1, var2, var3):
    return "{}/{}/{}/".format(var1, var2, var3)

这是追溯

Internal Server Error: /app/view1/
Traceback (most recent call last):
  File "C:\Python27\lib\site-packages\django\core\handlers\exception.py", line 41, in inner
    response = get_response(request)
  File "C:\Python27\lib\site-packages\django\core\handlers\base.py", line 249, in _legacy_get_response
    response = self._get_response(request)
  File "C:\Python27\lib\site-packages\django\core\handlers\base.py", line 187, in _get_response
    response = self.process_exception_by_middleware(e, request)
  File "C:\Python27\lib\site-packages\django\core\handlers\base.py", line 185, in _get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "C:\Code\app\views.py", line 216, in view1
    form.save()
  File "C:\Python27\lib\site-packages\django\forms\models.py", line 463, in save
    self.instance.save()
  File "C:\Python27\lib\site-packages\django\db\models\base.py", line 807, in save
    force_update=force_update, update_fields=update_fields)
  File "C:\Python27\lib\site-packages\django\db\models\base.py", line 837, in save_base
    updated = self._save_table(raw, cls, force_insert, force_update, using, update_fields)
  File "C:\Python27\lib\site-packages\django\db\models\base.py", line 923, in _save_table
    result = self._do_insert(cls._base_manager, using, fields, update_pk, raw)
  File "C:\Python27\lib\site-packages\django\db\models\base.py", line 962, in _do_insert
    using=using, raw=raw)
  File "C:\Python27\lib\site-packages\django\db\models\manager.py", line 85, in manager_method
    return getattr(self.get_queryset(), name)(*args, **kwargs)
  File "C:\Python27\lib\site-packages\django\db\models\query.py", line 1076, in _insert
    return query.get_compiler(using=using).execute_sql(return_id)
  File "C:\Python27\lib\site-packages\django\db\models\sql\compiler.py", line 1098, in execute_sql
    for sql, params in self.as_sql():
  File "C:\Python27\lib\site-packages\django\db\models\sql\compiler.py", line 1051, in as_sql
    for obj in self.query.objs
  File "C:\Python27\lib\site-packages\django\db\models\sql\compiler.py", line 1000, in pre_save_val
    return field.pre_save(obj, add=True)
  File "C:\Python27\lib\site-packages\django\db\models\fields\files.py", line 296, in pre_save
    file.save(file.name, file.file, save=False)
  File "C:\Python27\lib\site-packages\django\db\models\fields\files.py", line 93, in save
    name = self.field.generate_filename(self.instance, name)
  File "C:\Python27\lib\site-packages\django\db\models\fields\files.py", line 327, in generate_filename
    filename = self.upload_to(instance, filename)
TypeError: upload_path() takes exactly 3 arguments (2 given)

有人可以向我解释这个错误吗？感谢

修改

models.py

class Model1(models.Model):
    certno = models.CharField(max_length = 20)
    datecreated = models.DateTimeField(auto_now_add = True)
    pdf = models.FileField(upload_to = upload_path("apple", "cherry", "grapefruit"), null = True, blank = True)

    def __unicode__(self):
        return str(self.certno)

forms.py

class PatForm(forms.ModelForm):

    class Meta:
        model = Pat
        exclude = ['datecreated']
        labels = {
            'certno': _('Certificate Number'),
            'pdf': _('PDF'),
        }

Answer 1

您的upload_path函数必须接受2个参数instance和filename，但您已经定义了一个自定义函数，它接受3个参数，恰好是字符串。您应该更改upload_path功能，可能更像这样，

def upload_path(instance, filename):
    return "{}/{}".format(instance.certno, filename)

每当保存模型时，都会调用

upload_path函数或传递到upload_to中FileField选项的任何函数，并使用如上所述的明确参数。

在form.save（）

1 个答案: