Question

我试图调试我的网站错误我遇到了这个问题：

SyntaxError：意外的标识符＆＃39; oeuvre＆＃39;。预计要么关闭＆＃39;]＆＃39;或者＆＃39;，＆＃39;跟随数组元素。

这是代码的一部分：

<?php

$id_site = $_GET['id_site'];
include("include/heritage.php");

$num_vague = $_GET['num_vague'];


$req = $bdd->query("SELECT * FROM site where id_site = $_GET[id_site]");
while ($donnees = $req->fetch())
{
  $id_site = $donnees['id_site'];
  $id_client_site = $donnees['id_client_site'];
  $id_restaurateur_site = $donnees['id_restaurateur_site'];
  $nom_site = $donnees['nom_site'];
  $nom_site = str_replace("\"", "'", $nom_site);
  $cp_site = $donnees['cp_site'];
  $ville_site = $donnees['ville_site'];
  $adresse_site = $donnees['adresse_site'];

  $i2c_site = $donnees['i2c_site'];
}

这是包含的文件heritage.php：

<?php

$id_site = $_GET['id_site'];
$req_client = $bdd->query("SELECT nom_client FROM membre WHERE id_membre=" . $_SESSION['id_membre_login']);
$donnees_client = $req_client->fetch();
$client_name = $donnees_client['nom_client'];

if ($client_name != '') {
    $client_name = addslashes($client_name);
    $req_client = $bdd->query("SELECT * FROM client WHERE societe_client = '$client_name'");
    $donnees_client = $req_client->fetch();
    $passage_1_client = $donnees_client['passage_1_client'];
    $passage_2_client = $donnees_client['passage_2_client'];

    $couleur1 = $donnees_client['couleur1'];
    $couleur2 = $donnees_client['couleur2'];
    $couleur3 = $donnees_client['couleur3'];
}
if (isset($_GET['id_site'])) {
    $reqClientPassage = $bdd->query("
SELECT client.passage_1_client, client.passage_2_client
FROM site
INNER JOIN client ON client.id_client = site.id_client_site
WHERE id_site =" . $id_site
    );

    $donneesClientPassage = $reqClientPassage->fetch();

    $passage_1_client = $donneesClientPassage['passage_1_client'];
    $passage_2_client = $donneesClientPassage['passage_2_client'];
}
?>

感谢您的帮助！

Answer 1

尝试如下

$req = $bdd->query("SELECT * FROM site where id_site =". $_GET['id_site']); //single quote missing

Answer 2

更改以下行

$req = $bdd->query("SELECT * FROM site where id_site = $_GET[id_site]");

到

$id = $_GET['id_site'];
$req = $bdd->query("SELECT * FROM site where id_site = $id");

您的语法不正确

Answer 3

从以下查询中删除$_GET[id_site]并添加此$id_site变量

$req = $bdd->query("SELECT * FROM site where id_site = $_GET[id_site]");

到

$req = $bdd->query("SELECT * FROM site where id_site = $id_site");

意外的标识符预计结束＆＃39;]＆＃39;或者＆＃39;，＆＃39;跟随数组元素

3 个答案: