Question

尝试在此代码中设置用户数据并保持返回“抱歉，我的机器人代码存在问题”

internal static IDialog<SandwichOrder> MakeRootDialog()
    {
        return Chain.From(() => FormDialog.FromForm(SandwichOrder.BuildForm))
            .Do(async (context, order) =>
            {
                try
                {
                    var activity = context.Activity;
                    var channelId = activity.ChannelId;
                    var fromId = activity.From.Id;
                    var stateClient = activity.GetStateClient();
                    **var userData = await stateClient.BotState.GetUserDataAsync(activity.ChannelId, activity.From.Id);
                    // modify a property within user data 
                    userData.SetProperty<string>("SerialNumber", "");
                    // save updated user data
                    await stateClient.BotState.SetUserDataAsync(activity.ChannelId, activity.From.Id, userData);**

                    var completed = await order;
                    // Actually process the sandwich order...
                    await context.PostAsync("Defect data submitted!");

                }
                catch (HttpOperationException err)
                {
                    // handle error with HTTP status code 412 Precondition Failed
                }
                catch (FormCanceledException<SandwichOrder> e)
                {
                    string reply;
                    if (e.InnerException == null)
                    {

                        reply = $"You quit on {e.Last}--maybe you can finish next time!";
                    }
                    else
                    {
                        reply = "Sorry, I've had a short circuit.  Please try again.";
                    }

                    await context.PostAsync(reply);
                }
            });
    }

它实际上正在工作并清除属性，但我不想再看到该错误消息

Answer 1

使用对话框上下文的方法来操作对话框方法中的状态，而不是使用activity.GetStateClient（）。

正在发生的事情是加载对话框时反序列化状态，并在对话框完成时自动保存。如果在对话框中手动创建状态客户端并操纵状态，则在发生自动保存时会发生冲突。

编辑：这符合预期。

在控制器中：

GridLayoutManager  gridLayoutManager = new GridLayoutManager(MainActivity.this, 2);
recyclerView.setLayoutManager(gridLayoutManager);

表格：

RecyclerView

从Chain.From（）清除Bot状态数据.Do（）返回“抱歉，我的机器人代码有问题”

1 个答案: