我正在开发一个小Roslyn项目,包括更改解析树并将更改写回文件。我已经开始使用独立代码分析器,并希望将其构建为命令行应用程序。不过,我遇到了一个挑战。 使用: Find classes which derive from a specific base class with Roslyn部分地,主要是: https://github.com/dotnet/roslyn/wiki/Getting-Started-C%23-Syntax-Analysis我创建了这个小项目:
class Program
{
static void Main(string[] args)
{
try
{
if (args.Length < 1)
throw new ArgumentException();
SyntaxTree tree = CSharpSyntaxTree.ParseText(File.ReadAllText(args[0]));
var root = (CompilationUnitSyntax) tree.GetRoot();
var classes = from ClassDeclarationSyntax in root.DescendantNodesAndSelf() select ClassDeclarationSyntax;
foreach (var c in classes)
{
if (/*Not inheriting*/)
{
/*Add inherition*/
}
}
/*Write changes to file*/
}
catch (Exception e)
{
Console.WriteLine("Fatal error ocured.");
Console.WriteLine(e.Message);
Console.WriteLine(e.StackTrace);
}
}
}
作为代码中的注释状态,我需要检查类是否继承某个东西(并选择第二个选项)然后更改解析树,最后将其写入文件,现在我很高兴知道如何虽然我们也欢迎第二步和第三步的任何指示,但只检查“不继承”。要解析和更改的文件由路径作为程序参数提供:
if (args.Length < 1)
throw new ArgumentException();
SyntaxTree tree = CSharpSyntaxTree.ParseText(File.ReadAllText(args[0]));
<小时/> 解决方案
class Program
{
static void Main(string[] args)
{
try
{
if (args.Length < 1)
throw new ArgumentException();
SyntaxTree tree = CSharpSyntaxTree.ParseText(File.ReadAllText(args[0]));
var root = (CompilationUnitSyntax) tree.GetRoot();
IdentifierNameSyntax iname = SyntaxFactory.IdentifierName("Object");
BaseTypeSyntax bts = SyntaxFactory.SimpleBaseType(iname);
SeparatedSyntaxList<BaseTypeSyntax> ssl = new SeparatedSyntaxList<BaseTypeSyntax>();
ssl = ssl.Add(bts);
BaseListSyntax bls = SyntaxFactory.BaseList(ssl);
bool x = true;
while(x) //Way to handle all nodes due to impossibility to handle more than one in foreach
{
foreach (var c in root.DescendantNodesAndSelf())
{
x = false;
var classDeclaration = c as ClassDeclarationSyntax;
if (classDeclaration == null)
continue;
if (classDeclaration.BaseList != null) //Inherits
continue;
else //Not inherits
{
root = root.ReplaceNode(classDeclaration, classDeclaration.WithBaseList(bls));
x = true;
break;
}
}
}
if (args.Length > 1) //Write to given file
using (var sw = new StreamWriter(File.Open(args[1], FileMode.Open)))
{
root.WriteTo(sw);
}
else //Overwrite source
using (var sw = new StreamWriter(File.Open(args[0], FileMode.Open)))
{
root.WriteTo(sw);
}
}
catch (Exception e)
{
Console.WriteLine("Fatal error ocured.");
Console.WriteLine(e.Message);
Console.WriteLine(e.StackTrace);
}
}
}
答案 0 :(得分:0)
ClassDeclarationSyntax
的{{1}}包含BaseList
。因此,您可以使用以下字段检索有关基类的信息:
Types
不幸的是,您需要额外的逻辑来区分您的类具有基类或它只是实现接口。如果您想解决此问题,您需要使用 foreach (var c in correctRoot.DescendantNodesAndSelf())
{
var classDeclaration = c as ClassDeclarationSyntax;
if (classDeclaration == null)
{
continue;
}
if (classDeclaration.BaseList?.Types.Count > 0)
{
Console.WriteLine("This class has base class or it implements interfaces");
}
else
{
/*Add inherition*/
}
}
分析 基础对象 (类/接口)以获取有关相应semantical model
的信息或尝试如果在您的项目/解决方案中定义了此声明,则在ISymbol
中查找这些节点的声明。
此外,如果您想要向类添加继承,则需要使用syntax tree
和BaseList
SyntaxFactory.SimpleBaseType(...)
设置为新创建的节点