Question

我有以下代码：

for file in os.listdir('/home/sainik/Final/'+str(folderno)):
        if file.endswith('.csv'):
            print file
            with open(file,'rb') as csvfile:
                spamreader = csv.reader(csvfile)
                for row in spamreader:
                    print row

运行代码时，我收到以下错误：

Traceback (most recent call last):
  File "/home/sainik/Final/Programs/sainik.py", line 28, in <module>
    with open(file,'rb') as csvfile:
IOError: [Errno 2] No such file or directory: '4.csv'

请帮助。

Answer 1

您正在尝试从运行脚本的路径中打开文件。

您应该尝试打开完整路径

with open('/home/sainik/Final/' + file)

Answer 2

您只传递open函数的文件名。您应该将路径传递给open函数。将文件路径传递给open函数的两种可能方法，相对路径或完整路径。

尝试：

with open( os.path.join('/home/sainik/Final/',str(folderno),file),'rb') as csvfile:

Answer 3

您的脚本正在查看文件4.csv自己的目录。试试这样：

for file in os.listdir('/home/sainik/Final/'+str(folderno)):
        if file.endswith('.csv'):
            print file
            with open(/home/sainik/Final/'+str(folderno)+'\/'+file,'rb') as csvfile:
                spamreader = csv.reader(csvfile)
                for row in spamreader:
                    print row

在python中读取csv文件时出现IO错误

3 个答案: