Question

我需要更新表格中的以下列。男性，女性，婴儿和儿童使用SQL程序。从这个列paxtype有f，i，m，c.which分别是女性，婴儿，男性和儿童。但是我不能错误ORA-00907：缺少右括号

update xxxx a set (a.INFANTS,a.MALES,a.CHILDREN,a.FEMALES)=
(SELECT b.PAXTYPE, COUNT (b.PAXTYPE) FROM  xxxx b
(case ( count (b.PAXTYPE))
when  ( count (b.PAXTYPE))='M'then 'a.males'
when ( count (b.PAXTYPE))='F' then 'a.females'
when ( count (b.PAXTYPE))='I' then 'a.infants'
when ( count (b.PAXTYPE))='C' then 'a.children'
END)
     WHERE     a.date_key = TO_CHAR (b.FLIGHTDATE, 'RRRRMMDD')
           AND a.FLTNUM_KEY = TRIM (SUBSTR (b.flightnumber, 3))
           AND a.origin = b.frm
           AND a.destination = b.too
           --and a.date_key=20170801
           --and fightnumber = '100'
           AND TRIM (a.cancelled) IS NULL
 -- and rownum = 1 
  GROUP BY b.PAXTYPE;

）

Answer 1

看起来你想要每种类型的总数，对吗？我想这就是你想要做的。

update xxxx a set (a.INFANTS,a.MALES,a.CHILDREN,a.FEMALES)=
(SELECT 
    sum(case when b.PAXTYPE = 'I' then 1 else 0 end) as infants_count,
    sum(case when b.PAXTYPE = 'M' then 1 else 0 end) as males_count,
    sum(case when b.PAXTYPE = 'C' then 1 else 0 end) as children_count,
    sum(case when b.PAXTYPE = 'F' then 1 else 0 end) as females_count
FROM  xxxx b
     WHERE     a.date_key = TO_CHAR (b.FLIGHTDATE, 'RRRRMMDD')
           AND a.FLTNUM_KEY = TRIM (SUBSTR (b.flightnumber, 3))
           AND a.origin = b.frm
           AND a.destination = b.too
           --and a.date_key=20170801
           --and fightnumber = '100'
           AND TRIM (a.cancelled) IS NULL
 -- and rownum = 1 
  GROUP BY b.PAXTYPE);

oracle SQL过程更新表

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