Question

我正在尝试构建一个默认输入为空的函数，并将继续重复（如果用户输入任何内容，直到用户输入一个字符。问题是我被困在试图让输入问题重复出现在循环中。

#### Default
usr_int =("")

def str_analysis():
    usr_int = (input("enter word or integer: "))
    while (usr_int == ("")):
        if usr_int.isdigit():
            if (usr_int <= 99):
                return (usr_int, "is a smaller number than expected")
            elif (usr_int >= 100):
                return (usr_int, "is a pretty big number")
        elif usr_int.isalpha():
            if usr_int.isdigit():
                return (usr_int, "has multiple character types")
            else:
                return (usr_int, "is all alphabetical characters!")
        else:
            usr_int = (input("enter word or integer: "))
    
out_2 = str_analysis()
print(out_2)

Answer 1

几个月前，我想做一些与你现在该做的事情相同的事情。

我找到了一个功能

# Required library import
import msvcrt as m
while True :
    # The required function to use KeyButtonHIT
    if m.kbhit() :
        ch = m.getch().decode()
    else :
        ch = ''
    # Rest of the code in a loop

您可以类似地使用kbhit函数进行递归。

Answer 2

#### Default
usr_int =("")

def str_analysis():
    usr_int = (input("enter word or integer: "))
    while True:
     if usr_int.isdigit():
            if (int(usr_int) <= 99):
                return (usr_int, "is a smaller number than expected")
            elif (int(usr_int) >= 100):
                return (usr_int, "is a pretty big number")
     elif usr_int.isalpha():
            if usr_int.isdigit():
                return (usr_int, "has multiple character types")
            else:
                return (usr_int, "is all alphabetical characters!")
     else:
            usr_int = (input("enter word or integer: "))
    
out_2 = str_analysis()
print(out_2)

具有重复循环的函数

2 个答案: