Question

我正在努力操纵JS中的树对象，它可能很简单，但我找不到。

这是对象：

{
"100-silk": {
    "url": "https://www.striiiipes.com/product-category/100-silk/"
},
"apparel": {
    "url": "https://www.striiiipes.com/product-category/apparel/"
},
"ipad-accessories": {
    "url": "https://www.striiiipes.com/product-category/ipad-accessories/",
    "ipad-air": {
        "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-air/"
    },
    "ipad-mini": {
        "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-mini/"
    },
    "ipad-pro": {
        "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-pro/",
        "ipad-pro-12-9": {
            "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-pro/ipad-pro-12-9/"
        },
        "ipad-pro-9-7": {
            "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-pro/ipad-pro-9-7/"
        }
    }
}

我正在使用一个简单的递归函数来解决所有孩子：

function parseCategories(a) {
    if (typeof a === 'object') {
        $.each(a, function (i, v) {
            //if we only have a "url" object, then we're on last branch and can parse it
            if (Object.keys(v).length === 1 && 'url' in v) {
                //dosomething
            } else { // then we need to go deeper in the tree
                parseCategories(v);
            }
        })
    }
}

我想使用此功能来保存面包屑并获得如下对象：

"100-silk": {
    "categories" : ["100-silk"],
    "url": "https://www.striiiipes.com/product-category/100-silk/"
},
"apparel": {
    "categories" : ["apparel"],
    "url": "https://www.striiiipes.com/product-category/apparel/"
},
"ipad-accessories": {
    "categories" : ["ipad-accessories"],
    "url": "https://www.striiiipes.com/product-category/ipad-accessories/",
    "ipad-air": {
        "categories" : ["ipad-accessories", "ipad-air"],
        "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-air/"
    },
    "ipad-mini": {
        "categories" : ["ipad-accessories", "ipad-mini"],
        "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-mini/"
    },
    "ipad-pro": {
        "categories" : ["ipad-accessories", "ipad-pro"],
        "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-pro/",
        "ipad-pro-12-9": {
            "categories" : ["ipad-accessories", "ipad-pro", "ipad-pro-12-9"],
            "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-pro/ipad-pro-12-9/"
        },
        "ipad-pro-9-7": {
            "categories" : ["ipad-accessories", "ipad-pro", "ipad-pro-9-7"],
            "url": "https://www.striiiipes.com/product-category/ipad-accessories/ipad-pro/ipad-pro-9-7/"
        }
    }
}

};

所以重点是保存每个孩子和父母的完整面包屑。我该如何更改解析函数来获取此对象？我试图在每个循环中也传递父级，但我无法完全得到我想要的东西......

我在这里创建了jsfiddle。

非常感谢你的帮助！

Answer 1

您可以检查嵌套对象的属性并指定类别值。

如果

，它可以使用支票

object[k]是一个真正的价值，
typeof object[k] === 'object'，如果类型是对象，则
!Array.isArray(object[k])，如果实际属性不是数组，例如新添加的category，

然后它使用之前级别的类别并为其添加实际键来分配新属性category。

＆＃13;

function updateCategory(object) {        
    Object.keys(object).forEach(function (k) {
        if (object[k] && typeof object[k] === 'object' && !Array.isArray(object[k])) {
            object[k].category = (object.category || []).concat(k);
            updateCategory(object[k]);
        }
    });
}
var data = { "100-silk": { url: "URL/100-silk/" }, apparel: { url: "URL/apparel/" }, "ipad-accessories": { url: "URL/ipad-accessories/", "ipad-air": { url: "URL/ipad-accessories/ipad-air/" }, "ipad-mini": { url: "URL/ipad-accessories/ipad-mini/" }, "ipad-pro": { url: "URL/ipad-accessories/ipad-pro/", "ipad-pro-12-9": { url: "URL/ipad-accessories/ipad-pro/ipad-pro-12-9/" }, "ipad-pro-9-7": { url: "URL/ipad-accessories/ipad-pro/ipad-pro-9-7/" } } } };

updateCategory(data);

console.log(data);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

保存父级以构建树阵列

1 个答案: