Question

如何安排以下结果集

meal_type   menu_item_id
2           111
2           222
2           333
2           444
2           555
3           666
3           777
3           888
3           999

到

2       3
111     666
222     777
333     888
444     999
555

使用pivot或unpivot

Answer 1

您的数据存在问题 - 没有组来源，PIVOT假设聚合函数如果数据很小（主题为:-)），则可以使用ROW_NUMBER（）函数创建分组字段。我假设源表名是＆＃34; test＆＃34;

with ordered as (
  select 
  row_number() OVER (PARTITION by meal_type order by menu_item_id) num, 
  * from [test] 
)
select
max(case [meal_type] when 2 then [menu_item_id] end) as [2],
max(case [meal_type] when 3 then [menu_item_id] end)  as [3]
from ordered group by num

Answer 2

您可以使用ROW_NUMBER和PIVOT：

来获得结果

    SELECT  [2] ,
            [3]
     FROM    ( SELECT    * ,
                    ROW_NUMBER() OVER ( PARTITION BY meal_type ORDER BY menu_item_id ) R
          FROM      dbo.Meal
        ) s PIVOT( MAX(menu_item_id) FOR meal_type IN ( [2], [3] ) ) pvt;

两个列上的SQL Pivot

2 个答案: