我想创建一个Excel电子表格,并为每个变量插入相同数量的行。理想的结果看起来像列A& B在图片中。
到目前为止,我所能做的只是插入一个名字(列D& E),并且不知道对其余部分进行适当的枚举。
这就是我所拥有的:
import xlwt, xlrd
import os
current_file = xlwt.Workbook()
write_table = current_file.add_sheet('Sheet1')
name_list = ["Jack", "David", "Andy"]
food_list = ["Ice-cream", "Mango", "Apple", "Cake"]
total_rows = len(name_list) * len(food_list) # how to use it?
write_table.write(0, 0, "Jack")
for row, food in enumerate(food_list):
write_table.write(row, 1, food)
current_file.save("c:\\name_food.xls")
我怎么能为所有人做到这一点?谢谢。
答案 0 :(得分:4)
您可以按numpy.tile
和numpy.repeat
创建DataFrame
,然后删除a
列中的重复项:
df = pd.DataFrame({'a': np.repeat(name_list, len(food_list)),
'b': np.tile(food_list, len(name_list))})
df['a'] = np.where(df['a'].duplicated(), '', df['a'])
print (df)
a b
0 Jack Ice-cream
1 Mango
2 Apple
3 Cake
4 David Ice-cream
5 Mango
6 Apple
7 Cake
8 Andy Ice-cream
9 Mango
10 Apple
11 Cake
列表理解的另一种解决方案:
df = pd.DataFrame({'a': [y for x in name_list for y in [x] + [''] * (len(food_list)-1)],
'b': food_list * len(name_list)})
print (df)
a b
0 Jack Ice-cream
1 Mango
2 Apple
3 Cake
4 David Ice-cream
5 Mango
6 Apple
7 Cake
8 Andy Ice-cream
9 Mango
10 Apple
11 Cake
最后写to_excel
:
df.to_excel('c:\\name_food.xls', index=False, header=False)
答案 1 :(得分:3)
这样的事情应该有效:
import xlwt, xlrd
import os
current_file = xlwt.Workbook()
write_table = current_file.add_sheet('Sheet1')
name_list = ["Jack", "David", "Andy"]
food_list = ["Ice-cream", "Mango", "Apple", "Cake"]
for i, name in enumerate(name_list):
write_table.write(i * len(food_list), 0, name_list[i])
for row, food in enumerate(food_list):
write_table.write(i * len(food_list) + row, 1, food)
current_file.save("c:\\name_food.xls")
重要的部分是
write_table.write(i * len(food_list), 0, name_list[i])
你说那个名字应该写在第0,4,8,12行......
另外,部分
write_table.write(i * len(food_list) + row, 1, food)
将食物写入由行号增加的相应部分。