Question

我想从此为网站创建一些epg。由于我没有经验，不幸的是我很难

我有两个数组

 Array
 (
 [0] => Array
    (
        num] => 1
        [name] => name 1
        [epg_channel_id] => ch111
        [added] => 1505435915
    )

[1] => Array
    (
        num] => 2
        [name] => name 2
        [epg_channel_id] => ch222
        [added] => 1505435915
    )

[2] => Array
    (
        [num] => 3
        [name] => name 3
        [epg_channel_id] => ch333
        [added] => 1505435915
    )

[3] => Array
    (
        [num] => 4
        [name] => name 4
        [epg_channel_id] => ch444
        [added] => 1505435915

    )

第二个数组

 Array
 (
 [0] => Array
    (
        [ch000] => Um9jayBJbiBSaW8=
    )

[1] => Array
    (
        [ch111] => Um9jayBJbiBSaW8=
    )

[2] => Array
    (
        [ch222] => Um9jayBJbiBSaW8=
    )

[3] => Array
    (
        [ch333] => Um9jayBJbiBSaW8=
    )

[4] => Array
    (
        [ch444] => Um9jayBJbiBSaW8=
    )

我想输出这样的东西，使用epg_channel_id将第二个数组值推入第一个数组

Array
(
[0] => Array
(
    [num] => 1
    [name] => name 1
    [epg_channel_id] => ch111
    [added] => 1505435915
    [ch111] => Um9jayBJbiBSaW8=

)

我试过array_recursive，数组合并并没有用。我

Answer 1

如果两个数组中的相应索引保证具有相同的通道ID，则这将非常有效。例如，如果$ array1 [0]保证与$ array2 [0]具有相同的通道ID，则此解决方案将很好地工作：

$combined = [];
foreach($array1 as $key=>$val){
    $combined[$key] = $val + $array2[$key];
}

但是，如果不保证相应的索引具有相同的通道ID，则此解决方案将不起作用，并且您需要使用其他发布的答案之一。

如果您使用此方法，最后一个注意事项是，如果数组的大小不同，您将希望最大的数组为$ array1。所以，只需进行比较，看看哪个元素最多。

Answer 2

您必须遍历两个数组才能获得所需的结果：因为您必须将第一个数组的$arr1 = Array ( 0 => Array ( "num" => 1, "name" => "name 1", "epg_channel_id" => "ch111", "added" => "1505435915", ), 1 => Array ( "num" => 2, "name" => "name 2", "epg_channel_id" => "ch222", "added" => "1505435915", ), 2 => Array ( "num" => 3, "name" => "name 3", "epg_channel_id" => "ch333", "added" => "1505435915", ), 3 => Array ( "num" => 4, "name" => "name 4", "epg_channel_id" => "ch444", "added" => "1505435915", ), ); $arr2 = Array ( 0 => Array ( "ch000" => "Um9jayBJbiBSaW8=" ), 1 => Array ( "ch111" => "Um9jayBJbiBSaW8=" ), 2 => Array ( "ch222" => "Um9jayBJbiBSaW8=" ), 3 => Array ( "ch333" => "Um9jayBJbiBSaW8=" ), 4 => Array ( "ch444" => "Um9jayBJbiBSaW8=" ), ); $new_array = array(); foreach($arr1 as $key=>$value) { foreach($arr2 as $key1=>$value1) { foreach($value1 as $key2=>$value2) { if($key2 == $value['epg_channel_id']) { $value[$key2]=$value2; } } } $new_array[$key]=$value; } print_r($new_array);与第二个数组内部键匹配

{{1}}

DEMO

Answer 3

您可以使用第二个数组中的array_key_exists键存在或不存在，然后将其添加到新数组

工作演示：https://eval.in/863359

$array = Array
(
    Array
    (
        'num' => 1,
        'name' => 'name 1',
        'epg_channel_id' => 'ch111',
        'added' => '1505435915',
    ),

    Array
    (
        'num' => 2,
        'name' => 'name 2',
        'epg_channel_id' => 'ch222',
        'added' => '1505435915',
    ),

    Array
    (
        'num' => 3,
        'name' => 'name 3',
        'epg_channel_id' => 'ch333',
        'added' => '1505435915',
    ),

    Array
    (
        'num' => 4,
        'name' => 'name 4',
        'epg_channel_id' => 'ch444',
        'added' => '1505435915'

    )
);
$array2 = Array
(
    Array
    (
        'ch000' => 'Um9jayBJbiBSaW8='
    ),

    Array
    (
        'ch111' => 'Um9jayBJbiBSaW8='
    ),

    Array
    (
        'ch222' => 'Um9jayBJbiBSaW8='
    ),

    Array
    (
        'ch333' => 'Um9jayBJbiBSaW8='
    ),

    Array
    (
        'ch444' => 'Um9jayBJbiBSaW8='
    )
);

$newArray =[];
foreach ($array as $key => $value) {
    foreach ($array2 as $key2 => $value2) {
        if (array_key_exists($value['epg_channel_id'], $value2)) {
            $value[$value['epg_channel_id']] = $value2[$value['epg_channel_id']];
        }
    }
    $newArray[] = $value;
}

echo "<pre>"; 
print_r($newArray);

Answer 4

尝试阅读＆＃39; epg_channel_id＆＃39;的值来自array1 并通过获取＆＃39; ch111＆＃39;将其插入到array1本身来自array2

$ch_name = $array1[$i]['epg_channel_id'];
$id = $array1[$i]['num'];

$ch_value = $array2[$id]['$ch_name'];

$array1[$i]["$ch_name"] =  $ch_value;

尝试为每个数组添加foreach

Answer 5

array_merge_recursive适用于键为字符串的关联数组。将附加数字键。来自php.net

如果输入数组具有相同的字符串键，则这些键的值将合并到一个数组中，并且这是递归完成的，因此如果其中一个值是数组本身，则该函数将合并它另一个数组中的相应条目。但是，如果数组具有相同的数字键，则后面的值不会覆盖原始值，但会被追加。

您必须将数组转换为字符串键，或者使用一个循环逐个合并子数组。

Answer 6

试试这个。我希望它能解决你的问题。我测试了它。

foreach ($array1 as $key => $value){
       // echo $key;
        foreach ($array2 as $i =>$item){
            foreach ($item as $j=>$subitem){
                if($value['epg_channel_id'] == $j){
                    $array1[$key][$j] = $subitem;
            }
            }
        }
    }


print_r($array1);

Answer 7

ActiveSheet.Range("$A$1:$M$138").AutoFilter Field:=2, Criteria1:=Array("=*MY 18*", "=*MY18*") _
    , Operator:=xlAnd, Criteria2:="<>*discussion*"

合并具有相同键的两个数组或关联

7 个答案: