Question

我是C＃的新人如何获取JSON POST数据？我有一个POST JSON数据到我的asp.net的服务。

这里有数据：

{
   "transaction_time": "2017-09-18 09:47:54",
   "transaction_status": "capture",
   "transaction_id": "b7c8cfa9-b706-4a9d-b70d-8d70149145bd",
   "status_message": "Veritrans payment notification",
   "status_code": "200",
   "signature_key": "b22b5740bf2c587ba949ae5343757a66e5a75c45b9377b9ee891909bbd8977bb2caea8e0549bf09b5040b22f54efc76aa8beb31e321f9d600f267b23f37b30ae",
   "payment_type": "credit_card",
   "order_id": "LUHUMMLWOT",
   "masked_card": "401111-1112",
   "gross_amount": "326000.00",
   "fraud_status": "accept",
   "bank": "mandiri",
   "approval_code": "1505702878234"
 }

据我所知，我可以使用WebMethod捕获所有数据，创建一个方法然后初始化每个JSON对象的参数，但是每个帖子，它们都会发送不同的JSON。所以我必须获取所有JSON并动态地将其解析为变量。

请帮助：）

感谢〜

Answer 1

使用C＃发布

var client = new RestClient("http://localhost:8080/api/subject");
var request = new RestRequest(Method.POST);

request.AddHeader("cache-control", "no-cache");
request.AddHeader("content-type", "application/json");

request.AddParameter("application/json", "{\n        \"author\": "Balu\",\n        \"title\": \"Post using C#\"}", ParameterType.RequestBody);

IRestResponse response = client.Execute(request);

Answer 2

如果你不知道json将要发生什么，你必须在动态对象中解析你的json。

您可以像这样使用动态对象。

dynamic data = Json.Decode(json);

在你的情况下，你可以得到这样的数据。

string transaction_time=data.transaction_time;

Answer 3

你也可以使用object而不是dynamic，然后使用反射来获取json对象中的所有属性，我可以给你一般的代码示例，你可以在Reflection上搜索以获得更多的理解

public void GetData(object obj)
{
    foreach(var item in obj.GetType().GetProperties())
    {
         Console.WriteLine(item.Name + ":\t" + item.GetValue(obj));
    }
}

您可以按照您想要的方式使用它

Answer 4

   **Pleas do it step by step as below
    in Your Asp.net Java script using**



var yourPostJsonObject={
   "transaction_time": "2017-09-18 09:47:54",
   "transaction_status": "capture",
   "transaction_id": "b7c8cfa9-b706-4a9d-b70d-8d70149145bd",
   "status_message": "Veritrans payment notification",
   "status_code": "200",
   "signature_key": "b22b5740bf2c587ba949ae5343757a66e5a75c45b9377b9ee891909bbd8977bb2caea8e0549bf09b5040b22f54efc76aa8beb31e321f9d600f267b23f37b30ae",
   "payment_type": "credit_card",
   "order_id": "LUHUMMLWOT",
   "masked_card": "401111-1112",
   "gross_amount": "326000.00",
   "fraud_status": "accept",
   "bank": "mandiri",
   "approval_code": "1505702878234"
 }


$.ajax({
                type: 'POST',
                dataType: 'json',
                cache: false,
                url: 'SendTransaction', // webmethod or web serivces URL
                data: {jsonReceiverInCsharpObjecName:JSON.stringify(yourPostJsonObject)},
                success: function (response) {
                   alert('scucess')
                },
                error: function (jqXHR, textStatus, errorThrown) {
                    alert('Error - ' + errorThrown);
                }
            });

在Asp.net代码后面或webservice

using Newtonsoft.Json;
using System.Dynamic;
using Newtonsoft.Json.Converters;

public bool SendTransaction(string jsonReceiverInCsharpObjecName)
 {
   dynamic dynData =JsonConvert.DeserializeObject<ExpandoObject>
   (jsonReceiverInCsharpObjecName, new ExpandoObjectConverter());

foreach (KeyValuePair<string, object> transItem in dynData 
{
   if (transItem.Key == "transaction_time")
   var transaction_time = Convert.ToString(transItem.Value);
   else if (transItem.Key == "transaction_status")
   var transaction_status = Convert.ToString(transItem.Value);
   else if (transItem.Key == "transaction_id")
   var transaction_ido = Convert.ToString(transItem.Value);
   //else
   //do for rest attribute of your json data
 }

return true;
 }

在C＃中获取JSON POST数据

4 个答案: