我使用会话将dict从一个视图传递到另一个视图。但它显示了这个错误。我想创建多个模板提交表单。
我的 views.py
def view_qr_code(request, *args, **kwargs):
# here i wanna retrive session data
context = {
'code': 'qrcode'
}
return render(request, 'add_send_product.html', context)
def send_product_add(request):
form = SendProductForm(request.POST or None)
if request.method == 'POST':
if form.is_valid():
instance = form.save(commit=False)
data_dict = instance.__dict__
print data_dict
request.session['s'] = data_dict
return redirect('/qr-code/')
else:
messages.error(request, "Form is not valid")
context = {
'form': form,
'headline': 'Delivery Item'
}
return render(request, 'add_send_product.html', context)
urls.py
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^send-product/add/$', views.send_product_add, name='add_send_product'),
url(r'^qr-code/$', views.view_qr_code, name='qr_code'),
]
答案 0 :(得分:1)
不要序列化模型实例。序列化表单的cleaned_data
。
(我不确定你在这里做了什么,因为你从不保存实例。如果你这样做,我会说你应该只在会话中存储新创建的实例的ID。)
答案 1 :(得分:0)
由于您不想在send_product_add()方法中保存数据,因此您只需在会话变量中存储request.POST数据
def view_qr_code(request, *args, **kwargs):
# here i wanna retrive session data
data_dict = request.session.get('saved')
del data_dict['csrfmiddlewaretoken'] # middleware is not same here so
context = {
'code': 'qrcode'
}
return render(request, 'add_send_product.html', context)
def send_product_add(request):
form = SendProductForm(request.POST or None)
if request.method == 'POST':
if form.is_valid():
request.session['saved'] = request.POST
return redirect('/qr-code/')
else:
messages.error(request, "Form is not valid")
context = {
'form': form,
'headline': 'Delivery Item'
}
return render(request, 'add_send_product.html', context)