我正在写一个简单的类Pokemon程序，但当用户指定他们想要在他们的团队中有多少神奇宝贝时，我遇到了一个问题。 用户的团队有一个神奇宝贝的地图名称和口袋妖怪对象本身。
当游戏开始时，用户指定他们在团队中需要多少神奇宝贝。有一个预制的6个口袋妖怪阵列。默认的Pokemon构造函数将名称分配给2e14和-2e14之间的随机双精度。然后，for循环将指定数量的Pokemon对象添加到用户的团队并询问每个对象的统计数据。要求统计数据然后 的循环应该 ，对于每个条目，将其删除并放回一个条目，其中的密钥对应于输入的宠物小精灵名称。
我目前有以下问题： - ConcurrentModificationException
编辑：解决了。我使用预先制作的可能的pokemons数组中的对象来获取统计数据，然后一旦他们有了统计数据，就将它们添加到团队中，这样我就不必更改密钥了。 这是违法行为：
// for every Pokemon on the user's team, get the stats for them.
// Logic:
/* The for loop goes through the Map. For each entry, it saves the name of the pokemon
* and the pokemon itself, because if you don't, the key is just a random double, so
* the user can't call its name. This goes through and removes those entries,
* then re - inserts them back into the team, but this time the key corresponds to its name */
for(Map.Entry<String, Pokemon> entry : userTeam.team.entrySet()) {
// if the pokemon hasn't already gone through this procedure,
if(!entry.getValue().hasBeenStats) {
entry.getValue().getStats(input);
Pokemon pok = entry.getValue();
userTeam.team.remove(entry.getKey());
userTeam.addPokemon(pok);
}
}
如果您需要，可以使用以下一些其他代码段：
public class PokemonGame {
int userTeamSize;
PokemonTeam userTeam = new PokemonTeam();
// potential pokemon
Pokemon pok1 = new Pokemon();
Pokemon pok2 = new Pokemon();
Pokemon pok3 = new Pokemon();
Pokemon pok4 = new Pokemon();
Pokemon pok5 = new Pokemon();
Pokemon pok6 = new Pokemon();
// 0 1 2 3 4 5
Pokemon[] potentialUserPokemons = {pok1, pok2, pok3, pok4, pok5, pok6};
以下是应该接收一个数字的方法，该数字将是teamSize，然后将该数量的Pokemon从数组中添加到用户的团队中：
private void getUserSettings(Scanner input, PokemonTeam team) {
System.out.println("How many Pokemon do you want on your team?");
while(true) {
try {
int tempInt = Integer.parseInt(input.next());
if((tempInt > 6) || (tempInt < 1) ) {
System.out.println("Error: Enter valid team length.");
continue;
} else {
userTeamSize = tempInt;
}
break;
} catch(NumberFormatException e) {
System.out.println("Error: Try again");
continue;
}
}
input.nextLine();
}
private void setUpUserTeam(Scanner input) {
/* adds every Pokemon for the specified length into the users team, from the
* potential team array*/
for(int num = 0; num < userTeamSize; num++) {
userTeam.addPokemon(potentialUserPokemons[num]);
}
// for every Pokemon on the user's team, get the stats for them.
// Logic:
/* The for loop goes through the Map. For each entry, it saves the name of the pokemon
* and the pokemon itself, because if you don't, the key is just a random double, so
* the user can't call its name. This goes through and removes those entries,
* then re - inserts them back into the team, but this time the key corresponds to its name */
// this part is not working, it only run once
for(Map.Entry<String, Pokemon> entry : userTeam.team.entrySet()) {
// if the pokemon hasn't already gone through this procedure,
entry.getValue().getStats(input);
// save it's name --> key, and object --> pokemon for the value
String pokName = entry.getValue().getName();
Pokemon pok = entry.getValue();
userTeam.team.put(pokName, pok );
userTeam.team.remove(entry.getKey());
}
System.out.println("Pick a Pokemon to start with: ");
String pickedPokemon = input.nextLine();
// goes through the user's team, finds the Pokemon they specified, and sets it as the current pokemon
outerloop:
while (true) {
for(Map.Entry<String, Pokemon> entry : userTeam.team.entrySet()) {
if(entry.getKey().equals(pickedPokemon)) {
userTeam.setCurrentPokemon(entry.getValue());
break outerloop;
}
}
System.out.println("Error: Pokemon not found. Try again.");
}
}
在PokemonTeam中，有一个Map和一个方法可以将Pokemon添加到它：
Map<String, Pokemon> team = new HashMap<String, Pokemon>();
public void addPokemon(Pokemon pokemon) {
team.put(pokemon.getName(), pokemon);
/*teamSize is a different variable in PokemonTeam and once the
* Pokemons are added to the Map, will be the same as userTeamSize
* in class PokemonGame*/
teamSize = team.size();
}
这是来自Pokemon Class的getStats（）：
public void getStats(Scanner theInput) {
System.out.println("Please enter the stats of your pokemon: ");
System.out.println("Name: ");
// set the pokemon's name as what they enter
this.setName(theInput.nextLine());
// error handling
System.out.println("Level: ");
while(true) {
// if there is a wrong type entered it will repeat until correct
try {
this.setLevel(Integer.parseInt(theInput.next()));
} catch(NumberFormatException e) {
System.out.println("Error: Please try again.");
continue;
}
break;
}
System.out.println("Attack: ");
while(true) {
try {
this.setAttack(Integer.parseInt(theInput.next()));
} catch(NumberFormatException e) {
System.out.println("Error: Please try again.");
continue;
}
break;
}
System.out.println("Defense: ");
while(true) {
try {
this.setDefense(Integer.parseInt(theInput.next()));
} catch(NumberFormatException e) {
System.out.println("Error: Please try again.");
continue;
}
break;
}
System.out.println("Base: ");
while(true) {
try {
this.setBase(Integer.parseInt(theInput.next()));
} catch(NumberFormatException e) {
System.out.println("Error: Please try again.");
continue;
}
break;
}
System.out.println("STAB: ");
while(true) {
try {
this.setSTAB(Integer.parseInt(theInput.next()));
} catch(NumberFormatException e) {
System.out.println("Error: Please try again.");
continue;
}
break;
}
System.out.println("HP: ");
while(true) {
try {
int userHP = Integer.parseInt(theInput.next());
this.setMaxHP(userHP);
this.setCurrentHP(userHP);
this.setDamageAuto();
} catch(NumberFormatException e) {
System.out.println("Error: Please try again.");
continue;
}
break;
}
// gets the names of the moves and adds them to the map of moves and move infos
theInput.nextLine();
System.out.println("Name your Pokemon's 4 moves: ");
String moveNameOne = theInput.nextLine();
moves.put(moveNameOne, generateMoveInfo(moveNameOne));
String moveNameTwo = theInput.nextLine();
moves.put(moveNameTwo, generateMoveInfo(moveNameTwo));
String moveNameThree = theInput.nextLine();
moves.put(moveNameThree, generateMoveInfo(moveNameThree));
String moveNameFour = theInput.nextLine();
moves.put(moveNameFour, generateMoveInfo(moveNameFour));
hasBeenStats = true;
}
答案 0 :(得分：1)
除非您更改pickedPokemon的值，否则将永久打印Error: Pokemon not found. Try again.。
while (true) {
for(Map.Entry<String, Pokemon> entry : userTeam.team.entrySet()) {
if(entry.getKey().equals(pickedPokemon)) {
userTeam.setCurrentPokemon(entry.getValue());
break outerloop;
}
}
System.out.println("Error: Pokemon not found. Try again.");
}