php代码停止运行

时间:2017-09-17 09:26:45

标签: php mysql

我在过去几年里使用过这个脚本但突然出现了invaild用户或密码的错误,我没有改变代码和服务器的任何内容,所有的东西都有数据库/用户等等。任何人都有任何想法?以下是代码

<?php

session_start();
error_reporting(E_ALL | E_WARNING | E_NOTICE);
ini_set('display_errors', TRUE);

            $username = $_POST['emailnic'];
            $username = $_POST['password'];


            $INic=substr($username,0,5)."-".substr($username,5,7)."-".substr($username,12,1);
            include('con.php');
            $Query = mysql_query("SELECT NicNo,Email,Password,AcStatus,Actype FROM person WHERE NicNo='$INic' && Password='$password' || Email='$username' && Password='$password' ") or die(mysql_error());    


        $show=mysql_num_rows($Query);
        $result=mysql_fetch_array($Query);
        mysql_close($dbhandle); 
        if( $show >=1 )
         {


             $s=$result['AcStatus'];
             $t=$result['Actype'];
             $_SESSION['user_ACType']=$result['Actype'];
             $_SESSION['user_NIC']=$result['NicNo'];

            if($s==1 and $t==3)
            {

                header( 'Location: ../index_login.php' ) ;
            }
            else if($s==1 && $t==2)
            {

                header( 'Location: ../admin2.php' ) ;
            }
            else if($s==1 && $t==1)
            {

                header( "Location:../Admin.php" ) ;
            }
            else if($s==0 && $t==0)
            {
                  $_SESSION['error'] = "Your Account Avtivated After Varification!!!";


                header( "Location:../login.php" ) ;

            }

        }
        else{
                $_SESSION['error'] = "Invalid User Name or Password!!!";

                header( "Location:../login.php" ) ;

            }

?>

感谢 香美

1 个答案:

答案 0 :(得分:0)

Fromwhereyouaregettigvalofof $ password.checkthis =&gt; $ username = $ _POST ['emailnic'];             $ username = $ _POST ['password'];