Question

实际上我今天一直在练习一些java程序（试着自己学习）。我正在尝试编写一个程序，该程序接受来自用户的许多员工详细信息并显示它。我写了相同的代码，但失败了。那里没有编译错误。我试图创建一个ArrayList来放置从用户那里获得的细节。但不太确定如何做到这一点。或者应该通过使用对象数组来完成？

任何人都可以帮助我吗？另外请建议我改进编码的方法。我会非常感激的。

以下是我的代码：

public class EmployeeList{

    String empname;
    String empaddress;
    int empage;

    public void getEmployeeDetails(){
        try{
            final BufferedReader br =
                new BufferedReader(new InputStreamReader(System.in));
            System.out.println("Name :");
            empname = br.readLine();
            System.out.println("Address :");
            empaddress = br.readLine();
            System.out.println("Age :");
            empage = Integer.parseInt(br.readLine());
        }

        catch(final IOException e){

            e.printStackTrace();
        }
    }

    public void displayEmployeeDetails(){
        System.out.println("Name :" + empname);
        System.out.println("Address :" + empaddress);
        System.out.println("Age : " + empage);
    }
}

SerialisePersonList.java

public class SerialisePersonList{

    public static void main(final String[] args){
        final EmployeeList emp = new EmployeeList();
        System.out.println("Enter 3 person details");
        for(int i = 1; i <= 3; i++){
            System.out.println("Enter details of person" + i);
            final List details = new ArrayList();
            details.add(emp.getEmployeeDetails());
        }

        System.out.println("The entered person Details are as following");
        for(int i = 1; i <= 3; i++){
            System.out.println("Details of person" + i);
            emp.displayEmployeeDetails();
        }
    }
}

Answer 1

您需要在循环范围之前创建arraylist并在循环中添加特定员工

public static void main(String[] args) 
        {
           List<EmployeeList> details = new ArrayList<EmployeeList>();  
           System.out.println("Enter 3 person details");
           for(int i=1;i<=3;i++)
           {
               System.out.println("Enter details of person"+i);
               EmployeeList emp =new EmployeeList();
               emp.getEmployeeDetails();
               details.add(emp);
           }

           System.out.println("The entered person Details are as following");
           for(EmployeeList employee : details)
           {
               System.out.println("Details of person");
               employee.displayEmployeeDetails();
           }
        }

Answer 2

除了弗拉基米尔的改变之外，还有一些建议：

将EmployeeList重命名为Employee
制作List和ArrayList通用：List<Employee>和ArrayList<Employee>

Answer 3

你打电话给Class EmployeeList但是概念上它是Class Employee因为它代表一个员工，而不是一个列表他们。
Getter方法应该返回一些东西（不是无效的），在这种情况下，您应该重命名 getEmployeeDetails()来 readEmployeeDetails()更有意义。
emp和details不应该是最终的，它们不是常量，它们是变量。
您应该在main方法中为每个i创建一个新的Employee对象。

我认为你对列表和属于列表的元素有点混淆。

Answer 4

import java.io.BufferedReader;
import java.io.InputStreamReader;

public class Employee{

    private String name;
    private String address;
    private int age;

    public void setName(String name){
        this.name = name;
    }

    public void setAddress(String address){
        this.address = address;
    }

    public void setAge(int age){
        this.age = age;
    }

    public static Employee read() throws Exception{
        Employee tmp = new Employee();

        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));       

        System.out.println("Name :");
        tmp.setName(br.readLine());
        System.out.println("Address :");
        tmp.setAddress(br.readLine());
        System.out.println("Age :");
        tmp.setAge(Integer.parseInt(br.readLine()));

        return tmp;
    }

    public void display(){
        System.out.println("Name :" + this.name);
        System.out.println("Address :" + this.address);
        System.out.println("Age : " + this.age);
    }
}

其次是

import java.util.ArrayList;
public class SerialisePersonList{

    public static void main(final String[] args){
        ArrayList<Employee> list = new ArrayList<Employee>();

        System.out.println("Enter details for 3 people");
        for(int i = 1; i <= 3; i++){
            System.out.println("Enter details of person " + i);

            try{
                list.add(Employee.read());
            }catch(Exception e){
                e.printStackTrace();
            }
        }

        System.out.println("The entered person Details are as following");
        for(Employee emp : list){
            System.out.println("======================");
            emp.display();
        }
    }
}

应该涵盖它

创建对象数组

4 个答案: