我正在开设酒店专题页面。
我坚持使用的代码如下:
<?php
$result = mysqli_query($conn, "select * from facilities_type");
while($row = mysqli_fetch_assoc($result))
{
?>
<tr>
<th scope="row">
<input class="form-check-input" type="checkbox" id="blankCheckbox" name="room_feature_cb[]" value="<?php echo $row["facilitiestype_id"]; ?>">
</th>
<td>
<?php echo $row["room_facilities"] ?>
</td>
<td>
<img src="upload-img/icon/<?php echo $row["facilities_icon"]; ?>" width="25">
</td>
</tr>
<?php
}
?>
我想使用数组保存数据,但我无法将名称保存到数据库中
if (isset($_POST["room_feature_savebtn"]))
{
$feature = $_POST['room_feature_cb'];
for($result=0;$result>$feature;$result++)
{
mysqli_query($conn,"insert into facilities_details(facilitiestype_id) value ('$feature')");
}
}
答案 0 :(得分:1)
您可以使用foreach
,在这种情况下是更好的选择:
if (isset($_POST["room_feature_savebtn"]))
{
$features = $_POST['room_feature_cb'];
foreach ($features as $feature) {
mysqli_query($conn, "insert into facilities_details(facilitiestype_id) value ('$feature')");
}
}
你的错误是当你for
使用你在这里创建的数组索引($result
)时,尝试使用:
if (isset($_POST["room_feature_savebtn"]))
{
$feature = $_POST['room_feature_cb'];
for($result=0; $result < $feature; $result++) {
mysqli_query(
$conn,
"insert into facilities_details(facilitiestype_id) value ('" . $feature[$result] . "')"
);
}
}
我推荐foreach