Question

我有问题。每当我尝试创建Candy函数的对象时，所有属性似乎都可以正常创建。但是，每当我尝试运行draw函数时，都会使用最新创建的对象的所有属性，而不是我正在使用的属性。它总是会绘制我创建的第二个对象，但不会是第一个。我不知道为什么。我已经尝试了一切来尝试解决这个问题，所以如果在这段代码中看起来非常低效，那么这可能是我尝试修复此问题的众多尝试之一。你们知道这个问题吗？

以下是Candy功能的代码：

＆＃13;

Candy = function(img, location, canvas) {
	self = {}
	self.image = new Image()
	self.image.src = img
	self.location = {x: location.x, y: location.y}
	self.canvas = canvas
	self.draw = function() {
		self.canvas.drawImage(self.image, self.location.x, self.location.y, 132.4, 132.4)
	}
	self.move = function(FPS, seconds, location) {
		frames = FPS * seconds
		deltaX = (location.x - self.location.x) / frames
		deltaY = (location.y - self.location.y) / frames
		counter = 0
		setInterval(function() {
			self.location.x += deltaX
			self.location.y += deltaY
			counter++
			self.draw()
			if(counter >= frames)
				clearInterval()
		}, 1000 / FPS)
	}
	self.image.onload = function() {
		Candy.list.push(self)
		Candy.queue.splice(0, 1)
		
		if(Candy.queue.length == 0)
			draw()
		else
			Candy(Candy.queue[0].img, Candy.queue[0].location, Candy.queue[0].canvas)
	}
}
Candy.list = []
Candy.queue = []

＆＃13;

这是我称之为Candy功能的地方：

＆＃13;

gameStarted = true
	Candy.queue.push({img: "client/img/candy.png", location: {x: width / 3 - 87.5, y: height / 10}, canvas: canvasContext})
	Candy.queue.push({img: "client/img/candy2.png", location: {x: width / 3 - 87.5, y: 3 * (height / 10)}, canvas: canvasContext})
	
	Candy(Candy.queue[0].img, Candy.queue[0].location, Candy.queue[0].canvas)

＆＃13;

最后，这是绘图功能：

＆＃13;

function draw() {
	colorRect(0, 0, canvas.width, canvas.height, 'white');
	colorText("Player 1", 0.02, 0.05, "black", "40px Comic Sans");
	colorText("Player 2", 0.88, 0.05, "black", "40px Comic Sans");
	
	if(!gameStarted) {
		if(player1.ready)
			colorText("Ready", 0.02, 0.09, "green", "20px Comic Sans");
		else
			colorText("Not Ready", 0.02, 0.09, "red", "20px Comic Sans");
		if(player2.ready)
			colorText("Ready", 0.88, 0.09, "green", "20px Comic Sans");
		else
			colorText("Not Ready", 0.88, 0.09, "red", "20px Comic Sans");
		if(player1.ready && player2.ready)
			colorText("Press a button to start the game!", 0.32, 0.5, "black", "40px Comic Sans")
	}else{
		alert(Candy.list[0].image.src)
		alert(Candy.list[0].getImg())
		for(var i = 0; i < Candy.list.length; i++) {
			Candy.list[i].draw()
		}
		//TODO
	}
}

＆＃13;

Answer 1

好吧，我明白了。在这个函数中，我用这个取代了self，它解决了这个问题。无需任何回复。

Javascript - 对象中函数的属性，恢复为最新创建的对象

1 个答案: