Question

如何将值数据插入ajax返回的每个字段输入？

这是我的输入字段

    <div class="form-group col-sm-2 ">
    <label>Barcode</label>
    <div class="input-group input-group-sm">
        <input type="text" class="form-control" name="inputBarcode" id="inputBarcode" />
        <span class="input-group-btn">
            <button type="button" class="btn btn-info btn-flat"><i class="fa fa-search"></i></button>
        </span>                     
    </div>
</div>
<div class="form-group col-sm-4 input-group-sm">
    <label>Nama Barang</label>
    <input type="text" class="form-control" name="namaBarang" id="namaBarang" disabled/>
</div>
<div class="form-group col-sm-2 input-group-sm">
    <label>Satuan</label>
    <input type="text" class="form-control" name="satuanBarang" id="satuanBarang" disabled/>
</div>
<div class="form-group col-sm-2 input-group-sm">
    <label>Harga</label>
    <input type="text" class="form-control" name="hargaBarang" id="hargaBarang" disabled/>
</div>
<div class="form-group col-sm-2 ">
    <label>Jumlah</label>
    <div class="input-group input-group-sm">
        <input type="text" class="form-control" name="jumlahBarang" id="jumlahBarang" />
        <span class="input-group-btn">
            <button type="button" class="btn btn-info btn-flat">Add</button>
        </span>                     
    </div>
</div>

这是我的Ajax

$('#inputBarcode').blur(function(){

    var noBarcode=$('#inputBarcode').val();

    $.ajax({
       type:'post',
       url:'dataBarang.php',
       data:{barcode:noBarcode},

       success:function(response){
           $('#namaBarang').val(response);
       },

    });
});

这是来自ajax触发的查询

if(isset($_POST['barcode'])){

    $barcode=$_POST['barcode'];

    $qry=mysqli_query($koneksi, "SELECT * FROM tbl_barang WHERE id_barang='$barcode' ");

    WHILE ($res=mysqli_fetch_assoc($qry)){

        $namaBarang=$res['nama_barang'];
        $hargaNormal=$res['harga_jual_barang'];
        $qtyDiskon=$res['qty_diskon'];
        $hargaDiskon=$res['harga_qty_diskon'];

    }
}

Answer 1

从PHP返回JSON并在JS处解码并放置在INPUT FIELD

中

    if(isset($_POST['barcode'])){

$barcode=$_POST['barcode'];

$qry=mysqli_query($koneksi, "SELECT * FROM tbl_barang WHERE id_barang='$barcode' ");
$arr_data=array();
WHILE ($res=mysqli_fetch_assoc($qry)){

    $arr_data['namaBarang']=$res['nama_barang'];
    $arr_data['hargaNormal']=$res['harga_jual_barang'];
    $arr_data['qtyDiskon']=$res['qty_diskon'];
    $arr_data['hargaDiskon']=$res['harga_qty_diskon'];

}
echo json_encode($arr_data);

$('#inputBarcode').blur(function(){

    var noBarcode=$('#inputBarcode').val();

    $.ajax({
       type:'post',
       url:'dataBarang.php',
       data:{barcode:noBarcode},

       success:function(response){
           var obj=$.parseJSON(response);
           $('#namaBarang').val(obj.namaBarang);
       },

    });
});

从ajax返回值返回到输入字段

1 个答案: