Question

我想在Volley Library中解析这个JSON。我已经设置了我要解析配方和图像名称的所有内容。问题是我想要同时解析三个配方，但这里它有相同的对象名称Recipe，我不知道如何解析三个不同TextView的相同对象名称。

以下是JSON格式：link

这是我尝试的代码，但它给了我一个名字而不是三个不同的名字：

try {

  JSONArray list = response.getJSONArray("hits");

  Log.v ("MISH", "List: " + list);

  for (int x = 0; x<list.length(); x++) {
    JSONObject obj = list.getJSONObject(x);
    JSONObject main = obj.getJSONObject("recipe");
    String label = main.getString("label");
    String image = main.getString("image");

    Picasso.with(getApplicationContext()).load(image).into(recipeOne);

    Log.v("FISH", "NAME FATCH: " + label);
    recipeOneText.setText(label);

  }

Answer 1

试试这个。

在代码中使用optString：

try {
  if (TextUtils.isEmpty(response)) {
    Toast.makeText(this, "response is null", Toast.LENGTH_SHORT).show();
    return;
  }

  JSONObject jsonObject = new JSONObject(response);
  JSONArray hits = jsonObject.getJSONArray("hits");
  // edited here ,add data in your code
  JSONObject jo1 = hits.getJSONObject(0);
  hits.put(0,jo1); // add jo1 JSONObject to the JSON array, the angle is 0
  hits.put(1,jo1); // add jo1 JSONObject to the JSON array, the angle is 1
  hits.put(2,jo1); // add jo1 JSONObject to the JSON array, the angle is 2

  for (int i = 0; i < hits.length(); i++) {
    JSONObject jo = hits.getJSONObject(i);
    JSONObject recipe = jo.getJSONObject("recipe");
    String label = recipe.optString("label");
    String image = recipe.optString("image");

    Picasso.with(getApplicationContext()).load(image).into(recipeOne);

    Log.v("FISH", "NAME FATCH: " + label);
    recipeOneText.setText(label);
  }
} catch (JSONException e) {
   e.printStackTrace();
}

修改

// If your don't have to much data in your code , you can do like this . JSONObject jo1 = hits.getJSONObject(0); hits.put(0,jo1); // add jo1 JSONObject to the JSON array, the angle is 0 hits.put(1,jo1); // add jo1 JSONObject to the JSON array, the angle is 1 hits.put(2,jo1); // add jo1 JSONObject to the JSON array, the angle is 2

我想用齐射解析这个JSON，但我无法做到

1 个答案: