Question

我有一个像

这样的元组列表

data = [
    ('di', 'c1', 'avg11'),
    ('di', 'c2', 'stdev12'),
    ('eng', 'c1', 'stdev21'),
    ('eng', 'c2', 'stdev22')
]

如何将'di'和'eng'项目放入字典中，如下所示：

data1 = {'c1':'avg11','c2':'stdev12'}

data2 = {'c1':'stdev21','c2':'stdev22'}

使用pandas或numpy还是普通的python？

Answer 1

使用<nav id="site-navigation" class="main-navigation" role="navigation" aria-label="Menu supérieur"> <ul id="top-menu" class="menu"> <li a="" id="nav-menu-item-2105" class="main-menu-item menu-first menu-item-depth-0 menu-item menu-item-type-post_type menu-item-object-page menu-item-has-children has_children mega2"><a href="http://localhost/wordpress/commande/" class="menu-link main-menu-link"><span>Commande</span></a> <div class="sf-mega"> <div class="sf-mega-inner clearfix"> <ul class="navi first menu-depth-1"> <li a="" id="nav-menu-item-2106" class=" menu-item-depth-1 menu-item menu-item-type-post_type menu-item-object-page menu-item-has-children has_children normal_menu_item"><a href="http://localhost/wordpress/panier/" class="menu-link sub-menu-link"><span>Panier</span></a> <ul class="navi navi menu-depth-2"> <li a="" id="nav-menu-item-2107" class=" navi menu-item-depth-2 menu-item menu-item-type-post_type menu-item-object-page normal_menu_item"><a href="http://localhost/wordpress/boutique/" class="menu-link sub-menu-link"><span>Boutique</span></a></li> <li a="" id="nav-menu-item-2108" class=" navi menu-item-depth-2 menu-item menu-item-type-post_type menu-item-object-page normal_menu_item"><a href="http://localhost/wordpress/blog/" class="menu-link sub-menu-link"><span>Blog</span></a></li> <li a="" id="nav-menu-item-2109" class=" navi menu-item-depth-2 menu-item menu-item-type-post_type menu-item-object-page normal_menu_item"><a href="http://localhost/wordpress/about/page-markup-and-formatting/" class="menu-link sub-menu-link"><span>Page Markup And Formatting</span></a></li> </ul> </li> <li a="" id="nav-menu-item-2113" class=" menu-item-depth-1 menu-item menu-item-type-post_type menu-item-object-page menu-item-has-children has_children normal_menu_item"><a href="http://localhost/wordpress/panier/" class="menu-link sub-menu-link"><span>Panier</span></a> <ul class="navi navi menu-depth-2"> <li a="" id="nav-menu-item-2112" class=" navi menu-item-depth-2 menu-item menu-item-type-post_type menu-item-object-page normal_menu_item"><a href="http://localhost/wordpress/level-1/level-2/level-3a/" class="menu-link sub-menu-link"><span>Level 3a</span></a></li> <li a="" id="nav-menu-item-2111" class=" navi menu-item-depth-2 menu-item menu-item-type-post_type menu-item-object-page normal_menu_item"><a href="http://localhost/wordpress/level-1/level-2/level-3b/" class="menu-link sub-menu-link"><span>Level 3b</span></a></li> <li a="" id="nav-menu-item-2110" class=" navi menu-item-depth-2 menu-item menu-item-type-post_type menu-item-object-page normal_menu_item"><a href="http://localhost/wordpress/about/page-image-alignment/" class="menu-link sub-menu-link"><span>Page Image Alignment</span></a></li> </ul> </li> </ul> </div> </div> </li> <li a="" id="nav-menu-item-2114" class="main-menu-item menu-item-depth-0 menu-item menu-item-type-post_type menu-item-object-page menu-item-has-children has_children normal_menu_item"><a href="http://localhost/wordpress/boutique/" class="menu-link main-menu-link"><span>Boutique</span></a> <ul class="navi first menu-depth-1"> <li a="" id="nav-menu-item-2115" class=" menu-item-depth-1 menu-item menu-item-type-post_type menu-item-object-page menu-item-has-children has_children normal_menu_item"><a href="http://localhost/wordpress/page-d-exemple/" class="menu-link sub-menu-link"><span>Page d’exemple</span></a> <ul class="navi navi menu-depth-2"> <li a="" id="nav-menu-item-2116" class=" navi menu-item-depth-2 menu-item menu-item-type-post_type menu-item-object-page normal_menu_item"><a href="http://localhost/wordpress/page-b/" class="menu-link sub-menu-link"><span>Page B</span></a></li> </ul> </li> </ul> </li> </ul> </nav>你可以做

Pandas

Answer 2

在纯Python中，只需构建一个顶级字典，如果仍然缺少，使用dict.setdefault()来实现嵌套字典：

result = {}
for outer, inner, value in data:
    result.setdefault(outer, {})[inner] = value

这是对数据进行分组的最简单，更易读的方法。

演示：

>>> data = [
...     ('di', 'c1', 'avg11'),
...     ('di', 'c2', 'stdev12'),
...     ('eng', 'c1', 'stdev21'),
...     ('eng', 'c2', 'stdev22')
... ]
>>> result = {}
>>> for outer, inner, value in data:
...     result.setdefault(outer, {})[inner] = value
...
>>> result
{'di': {'c1': 'avg11', 'c2': 'stdev12'}, 'eng': {'c1': 'stdev21', 'c2': 'stdev22'}}

如果必须之后有data1和data2个变量，只需在'di'和'eng'键中设置：

data1 = result['di']
data2 = result['eng']

但如果你有更多或更少或不同的外键，这是相当不灵活的。

Answer 3

使用普通的python你可以做到

 def process_data(data):
    res = {}

    for itm in data:
        if itm[0] not in res:
            res[itm[0]] = {}
        res[itm[0]][itm[1]] = itm[2] 
    return res

使用示例：

>>> d = [
...     ('di', 'c1', 'avg11'),
...     ('di', 'c2', 'stdev12'),
...     ('eng', 'c1', 'stdev21'),
...     ('eng', 'c2', 'stdev22')
... ]
>>> print(process_data(d))
{'eng': {'c2': 'stdev22', 'c1': 'stdev21'}, 'di': {'c2': 'stdev12', 'c1': 'avg11'}}

Answer 4

使用itertools.groupby()功能：

import itertools

data = [
    ('di', 'c1', 'avg11'), ('di', 'c2', 'stdev12'),
    ('eng', 'c1', 'stdev21'), ('eng', 'c2', 'stdev22')
]
result = {k: {i[1]:i[2] for i in g}
           for k,g in itertools.groupby(sorted(data), key=lambda x: x[0])}
print(result)

输出：

{'di': {'c1': 'avg11', 'c2': 'stdev12'}, 'eng': {'c1': 'stdev21', 'c2': 'stdev22'}}

数据结构;将元组列表转换为字典

4 个答案: