Question

美好的一天，我有一个PHP代码，有一个$ _POST [＆＃39;查询＆＃39;]功能，我想用$ _POST [＆＃39;标签＆＃39;]添加它但是如何在android中传递2个变量对于PHP，我已经用我的代码将一个值传递给了$ _POST [＆＃39;查询＆＃39;]但是如何通过第二个呢？

OutputStream os = con.getOutputStream();
        BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));
        String data = URLEncoder.encode("Query", "UTF-8")+"="+URLEncoder.encode(query,"UTF-8");
        bw.write(data);
        bw.flush();

        con.connect();

        bw.close();
        os.close();

Answer 1

只需在&

附加另一个参数即可

String data = URLEncoder.encode("Query", "UTF-8")+"="+URLEncoder.encode(query,"UTF-8");
       data+= "&"+URLEncoder.encode("Tags", "UTF-8")+"="+URLEncoder.encode(yourTags,"UTF-8");

注意：为提高效率StringBuilder

StringBuilder params = new StringBuilder();
params.append(URLEncoder.encode("Query", "UTF-8")+"="+URLEncoder.encode(query,"UTF-8"));
params.append("&");
params.append(URLEncoder.encode("Tags", "UTF-8")+"="+URLEncoder.encode(yourTagStr,"UTF-8"));
bw.write(params.toString());
// ... code

在php android中传递2个变量

1 个答案: