初始化具有多个依赖项的RAC ReactiveSwift属性?

时间:2017-09-16 07:15:39

标签: ios swift mvvm reactive-cocoa reactive-swift

我使用ReactiveSwift和ReactiveCocoa相当新,我似乎已经找到了关于初始化具有依赖关系的Property的正确方法的障碍。

例如在下面的代码中,我尝试初始化一个Property但是我得到了一个预期的编译器错误。我的问题是如何/什么是“正确”的方法来做到这一点。

class SomeViewModel {
// illustration purposes, in reality the property (dependency) we will observe will change over time
let dependency = Property(value: true)
let dependency2 = Property(value: "dependency2")
let dependency3 = Property(value: 12345)
let weightLabel: Property<String>

// private(set) var weightLabel: Property<String>!
// using private(set) var weightLabel: Property<String>! works, 
// however this changes the meaning behind using let, because we could
// reinitalize weightLabel again which is not similar to using a let so not a good alternative

// let weightLabel: Property<String> = Property(value: "")
// another solution that will work but will result in a wrong value
// upon initalization then, changed into the "correct value" thus, i
// am discrading this as well

init() {
    weightLabel = dependency.map {
        // compiler error, 'self' captured by closure before all members were initalized. 
        // My question is if there is a way to handle this scenario properly
        if $0 && self.dependency2.value == "dependency2" && self.dependency3.value == 12345 {
            return ""
        }
        return ""
    }
}
}

正如您在评论中可能已经注意到的那样,我想知道是否有办法用ReactiveSwift处理这种情况,那么我上面提到的并不是非常理想的解决方案。

1 个答案:

答案 0 :(得分:3)

适合该场景的工具是combineLatest,它提供所有这些属性(流)的组合版本,无论何时更新它们。

weightLabel = Property.combineLatest(dependency, dependency2, dependency3)
    .map { d1, d2, d3 in
        return "Hello World! \(d1) \(d2) \(d3)"
    }

关于编译器错误,问题是您在初始化每个存储的属性之前捕获/引用闭包中的self。根据意图,您可以使用捕获列表直接捕获您感兴趣的值和对象,而不是self

let title: String
let action: () -> Void

init() {
    title = "Hello World!"

    //  `action` has not been initialised when `self` is
    // being captured.
    action = { print(self.title) } 

    // ✅ Capture `title` directly. Now the compiler is happy.
    action = { [title] in print(title) }
}