我一直在尝试进行对象序列化,反序列化程序。当我直接在FileInputStream中提供文件名时,我的程序运行得非常好,我能够成功地反序列化对象。但是当我尝试使用FileDialog时,序列化程序运行良好,但无法进行反序列化。我收到以下错误:
java.io.FileNotFoundException: nullnull (The system cannot find the file specified)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at package1.Deserialisation.main(Deserialisation.java:22)
Exception in thread "main" java.lang.NullPointerException
at package1.Deserialisation.main(Deserialisation.java:43) .
任何人都可以帮我解决同样的问题而且还要解释其原因,以免错误再次发生..
以下是我的代码:
package package1;
public class Employee implements java.io.Serializable
{
private static final long serialVersionUID = 2L;
String name;
String address;
int age;
//int SSN;
transient int SSN;
public void checkDetails()
{
System.out.println("The check details for the employee" + name + "are :");
}
}
Serialisation:
package package1;
import java.awt.FileDialog;
import java.awt.Frame;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectOutputStream;
public class Serialization
{
public static void main(String[] args)
{
Employee emp =new Employee();
emp.name="vidhya";
emp.address="XYZ";
emp.age=26;
emp.SSN=123456;
try
{
FileDialog fd =new FileDialog(new Frame(),"Save As...",FileDialog.SAVE);
fd.setVisible(true);
String filepath=new String (fd.getDirectory()+fd.getFile());
FileOutputStream fileout =new FileOutputStream(filepath);
ObjectOutputStream objout=new ObjectOutputStream(fileout);
objout.writeObject(emp);
fileout.close();
objout.close();
}
catch (IOException e2) {
e2.printStackTrace();
}
}
}
Deserialisation :
package package1;
import java.awt.FileDialog;
import java.awt.Frame;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
public class Deserialisation
{
static Employee emp=null;
public static void main(String[] args)
{
try {
FileDialog fd1 =new FileDialog(new Frame(),"Open...",FileDialog.LOAD);
String filepath = new String(fd1.getDirectory() + fd1.getFile());
FileInputStream filein =new FileInputStream(filepath);
ObjectInputStream objin =new ObjectInputStream(filein);
emp=(Employee) objin.readObject();
objin.close();
filein.close();
}
catch (IOException e)
{
e.printStackTrace();
}
catch (ClassNotFoundException e1)
{
System.out.println("Employee class not found");
e1.printStackTrace();
return;
}
System.out.println("Employee Name : " + emp.name);
System.out.println("Address :" + emp.address);
System.out.println("Age : " + emp.age);
System.out.println("SSN :" + emp.SSN);
}
}
答案 0 :(得分:4)
String filepath = new String(fd1.getDirectory() + fd1.getFile());
这是创建“nullnull”的路径,这意味着这两个值都为null。
尝试在上面一行之前使用fd1.show();
。
编辑:正如Viydha所指出的那样,show()已被弃用,应该使用setVisible()。
答案 1 :(得分:1)
错误发生在FileDialog
。这一行:
String filepath = new String (fd.getDirectory()+fd.getFile());
创建nullnull
的路径。您应该在此行之前执行fd.show();
,或者更好地使用JFileChooser