我正在使用简单的for循环创建动态if($dateweekday ==='Tuesday'){
for ($v=1;$v<=4;$v++){
$ttt = 'tuesday_'.$v;
}
echo $_SESSION[$ttt] = $newdateformat ;
echo "<br>";
}
变量来打印日期。
2017-9-19
2017-9-26
2017-10-03
2017-10-10
结果
$_SESSION[$ttt]
看起来不错。但后来我关心的是$_SESSION['tuesday_1'] = 2017-9-19;
$_SESSION['tuesday_2'] = 2017-9-26;
$_SESSION['tuesday_3'] = 2017-10-03;
$_SESSION['tuesday_4'] = 2017-10-10;
的价值。结果应该是
var_dump($_SESSION[$ttt])
当我string(10)
string(9)
string(9)
string(9)
这就是我得到的
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.Statement;
public class Main {
public static void main(String[] args) throws Exception {
Connection conn = null;
Statement stmt = null;
ResultSet rs = null;
PreparedStatement pstmt = null;
try {
// SETUP
Class.forName("com.mysql.jdbc.Driver");
conn = DriverManager.getConnection("jdbc:mysql://...");
stmt = conn.createStatement();
stmt.execute("DROP TABLE IF EXISTS ttt");
stmt.execute("CREATE TABLE ttt (value FLOAT)");
// INPUT VALUE
float input = 1.223473E6f;
print(" Input", input);
pstmt = conn.prepareStatement("INSERT INTO ttt VALUES (?)");
pstmt.setFloat(1, input);
pstmt.execute();
// OUTPUT VALUES
rs = stmt.executeQuery("SELECT value, "
+ "AVG(value) as avg, MIN(value) as min, "
+ "MAX(value) as max, value + 0 as plus, "
+ "value * 1 as mult, "
+ "cast(value as decimal) as valcast "
+ "FROM ttt;");
rs.next();
System.out.println();
print("Output", rs.getFloat("value"));
print(" AVG", rs.getFloat("avg"));
print(" MIN", rs.getFloat("min"));
print(" MAX", rs.getFloat("max"));
print(" +0", rs.getFloat("plus"));
print(" *1", rs.getFloat("mult"));
print(" CAST", rs.getFloat("valcast"));
} finally {
if (stmt != null)
stmt.close();
if (pstmt != null)
pstmt.close();
if (conn != null)
conn.close();
}
}
private static void print(String name, float value) {
System.out.println(name + ": " + value + " (0x"
+ Integer.toHexString(Float.floatToRawIntBits(value)) + ")");
}
我该如何做到这一点?
答案 0 :(得分:0)
我注意到两件事:
<强> 1 强>
假设我们将$t
设置为'value_before'
:
$t = 'value_before';
现在:
echo $t = 'value_after';
以上代码等于:
$t = 'value_after';
echo $t;
所以结果是回显'value_after',你永远不会回显旧值('value_before')。
2。我注意到的另一件事是你在一个循环中多次准备变量,然后你只回显一次,代码的这一部分:
for ($v=1;$v<=4;$v++){
$ttt = 'tuesday_'.$v;
}
echo $_SESSION[$ttt] = $newdateformat;
因此,您回复的唯一内容是'$_SESSION['tuesday_4'] = $newdateformat'
,并且tuesday_1
,tuesday_2
,tuesday_3
的ano不会被回显/修改。