Question

from math import pi, exp, sqrt

m = 0
s = 1
n = 10

min_value = m - 5*s
max_value = m + 5*s
dv = (max_value - min_value)/(n-1)
values = []
for i in range(n):
    value = min_value + i*dv
    values.append(value)

def gaussian2(values):
    for x in values:
        y = (1/(sqrt(2*pi)*s))*exp(-0.5*((x - m)/s)**2) # Formel
        return y
        print(y)

嗨，我正在尝试获取函数从表值中获取x值，但它不起作用。我无法打印列表值，因此我的功能一定有问题。有什么提示吗？

试过这个，这是一个好的解决方案吗？

from math import pi, exp, sqrt

m = 0
s = 2
n = 10

def gaussian2(m,s,x):
        y = (1/(sqrt(2*pi)*s))*exp(-0.5*((x - m)/s)**2) # Formel
        return y

min_value = m - 5*s
max_value = m + 5*s
dv = (max_value - min_value)/(n-1)
values = []
for i in range(n):
    value = min_value + i*dv
    values.append(value)
print("    x    y")
for x in values:
    y = gaussian2(m,s,x)
    print("%5.1f %5.1f" % (x,y))

Answer 1

这是怎么回事？

from math import pi, exp, sqrt

m = 0
s = 1
n = 10

min_value = m - 5*s
max_value = m + 5*s
dv = (max_value - min_value)/(n-1)
values = []
for i in range(n):
    value = min_value + i*dv
    values.append(value)

# print(values)

def gaussian2(vals, debug=True):
    if type(vals) is list:
        if debug:
            print("input len = {0}".format(len(vals)))
        y = []
        t=0
        for x in vals:
            yi = (1/(sqrt(2*pi)*s))*exp(-0.5*((x - m)/s)**2) # Formel
            y.append(yi)
            t+=1
            if debug:
                print("{2}: x = {0}, y = {1}".format(x,yi,t))
        return y

print(gaussian2(values))

Answer 2

在print语句之前和循环内部的最后一个函数中有return语句。一旦到达return语句，循环就会停止运行。这种修改应该可以解决问题：

from math import pi, exp, sqrt

m = 0
s = 1
n = 10

min_value = m - 5*s
max_value = m + 5*s
dv = (max_value - min_value)/(n-1)
values = []
for i in range(n):
    value = min_value + i*dv
    values.append(value)

def gaussian2(values):
    for x in values:
        y = (1/(sqrt(2*pi)*s))*exp(-0.5*((x - m)/s)**2) # Formel
        print(y)
    return y

Answer 3

更简单的解决方案是执行以下操作：

from math import pi, exp, sqrt

m = 0
s = 1
n = 10
min_value = m - 5*s
max_value = m + 5*s
dv = (max_value - min_value)/(n-1)


Xvalues = [min_value + i *dv for i in range(n)]
Yvalues = [1/(1/(sqrt(2*pi)*s))*exp(-0.5*((x - m)/s)**2) for x in Xvalues]

for y in Yvalues :
    print(y);

使函数从列表中获取x值。列表没问题，功能无效

3 个答案: