Question

我有一个表单，它从我的数据库中检索各种值并在表单中显示它。表单包含文本框，收音机，下拉菜单。检索部分工作正常，并为每个字段显示正确的值。但是当我想要更改字段并更新数据时，它不会更新。有人可以帮我这个。这是我的代码：

if(isset($_POST['submit'])){
    $sql = "UPDATE tbl_dealer_info ";
    $sql .= "SET phone = '$phone', email = '$email', sfid = '$sfid', ... WHERE id = '$idhidden' ";
    $result = mysqli_query($conn, $sql);
    if(!$result){
        die('Could not update data: '. mysqli_error());
    }
    else{
        echo "Updated Successfully";
    }
}
<input type = "hidden" name = "idhidden" id = "idhidden" value = "" /> // My hidden input to store the id

显示＆＃34;已成功更新＆＃34;但实际上并没有更新。

Answer 1

你缺少sql语句中的条件和';'

$sql = "UPDATE tbl_dealer_info ";
$sql .= "SET phone = '$phone', email = '$email', sfid = '$sfid' WHERE #here where condition #here ";

Answer 2

试试这个

if(isset($_POST['submit'])){
    $sql = "UPDATE tbl_dealer_info SET phone = '".$phone."', email = '".$email."', sfid = '".$sfid."', ... WHERE id = ".$idhidden; 
     $result = mysqli_query($conn, $sql);
     if(!$result){ 
        die('Could not update data: '.  mysqli_error()); 
     } else{ 
        echo "Updated Successfully";
    } 
 }

使用php更新mysqli数据

2 个答案: