我正在尝试设置我的应用程序以与服务器通信,以便我可以执行配置文件crud。我设置了一个工厂,当点击它将创建一个JSONObject并将该数据发布到服务器时,所有代码似乎都没问题,但在“new SendUserDetails.execute(”server_URL“,postData.toString());”说它无法解析符号执行。有没有我忽略的东西?非常感谢您的帮助。
edit_profile.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
JSONObject postData = new JSONObject();
try{
postData.put("Name", name.getText().toString());
postData.put("Bio", bio.getText().toString());
postData.put("Age", age.getText().toString());
postData.put("Major", major.getText().toString());
postData.put("College", college.getText().toString());
postData.put("Random Fact", random_fact.getText().toString());
new SendUserDetails.execute("server_URL", postData.toString());
} catch (JSONException e) {
e.printStackTrace();
}
}
});
这是Http连接的代码
private class SendUserDetails extends AsyncTask<String, Void, String>{
@Override
protected String doInBackground(String... params) {
String data = "";
HttpURLConnection httpURLConnection = null;
try{
httpURLConnection = (HttpURLConnection) new URL(params[0]).openConnection();
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(httpURLConnection.getOutputStream());
wr.writeBytes("PostData" + params[1]);
wr.flush();
wr.close();
InputStream in = httpURLConnection.getInputStream();
InputStreamReader inputStreamReader = new InputStreamReader(in);
int inputStreamData = inputStreamReader.read();
while(inputStreamData != -1){
char current = (char) inputStreamData;
inputStreamData = inputStreamReader.read();
data += current;
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(httpURLConnection != null){
httpURLConnection.disconnect();
}
}
return data;
}
@Override
protected void onPostExecute(String result){
super.onPostExecute(result);
Log.e("TAG", result);
}
}
答案 0 :(得分:0)
在SendUserDetails
之后添加parens,因为您正在尝试调用构造函数。换句话说,将new SendUserDetails.execute(...)
替换为new SendUserDetails().execute(...)
。