Question

我有一个输入字符串：

result = '"testing","0.8841","642000.0","80.014521","-60.940653","4522126666","1500854400","","1500842014000","name","80.014521","-60.996532","sampledevice","3","name"'

data = result.split("\n")

i = 0
while i < len(data):
    i = i +1 
    dd = data[i].split(',')
    print dd
    break

并输出相应的输出：

[
  '"testing"',
  '"0.8841"',
  '"642000.0"',
  '"80.014521"',
  '"-60.940653"',
  '"4522126666"',
  '"1500854400"',
  '""',
  '"1500842014000"',
  '"name"',
  '"80.014521"',
  '"-60.996532"',
  '"sampledevice"',
  '"3"',
  '"name"'
]

如何从列表中的每个元素中删除单引号？

Answer 1

您需要应用strip来删除字符串两边的引号。

dd = [x.strip('"') for x in data[i].split(',')]

说，你的循环似乎有一个索引问题。应该重写，例如：

result = '"testing","0.8841","642000.0","80.014521","-60.940653","4522126666","1500854400"\n"1500842014000","name","80.014521","-60.996532","sampledevice","3","name"'

for line in result.splitlines():
    dd = [x.strip('"') for x in line.split(',')]
    print(dd)

此时，

你会更好

dd = ast.literal_eval(line)

还完美地使用csv模块并输入list（不需要传递文件句柄）（不要传递string，因为它会产生一些奇怪的效果）

导入csv

for row in csv.reader(result.splitlines()):
    print(row)

全部导致：

['testing', '0.8841', '642000.0', '80.014521', '-60.940653', '4522126666', '1500854400']
['1500842014000', 'name', '80.014521', '-60.996532', 'sampledevice', '3', 'name']

Answer 2

将文本视为CSV：

import csv
import StringIO

result = '"testing","0.8841","642000.0","80.014521","-60.940653","4522126666","1500854400","","1500842014000","name","80.014521","-60.996532","sampledevice","3","name"'
print next(csv.reader(StringIO.StringIO(result)))

给你：

['testing', '0.8841', '642000.0', '80.014521', '-60.940653', '4522126666', '1500854400', '', '1500842014000', 'name', '80.014521', '-60.996532', 'sampledevice', '3', 'name']

Answer 3

在拆分之前

替换双引号：

>>> result.replace('"', '').split(',')
['testing', '0.8841', '642000.0', '80.014521', '-60.940653', '4522126666', '1500854400', '', '1500842014000', 'name', '80.014521', '-60.996532', 'sampledevice', '3', 'name']

Answer 4

literal_eval是解决此问题的好方法

import ast
dd = [ast.literal_eval(i) for i in data]

Answer 5

首先：输出字符串中没有单引号。你有什么是用双引号引用的字符串（可能存储在// ~/components/general/Page.vue <template lang="pug"> div(id="page" class="align-center") slot </template>文件中）。您在输出中看到的单引号实际上是确定字符串。所以：

csv

实际上是

'"some_string"'

第二：如果你想删除双引号，你可以这样做：

"some_string"

看下面的陈述，应该更清楚：

for item in data.split(","):
    print(item.strip('"'))

Answer 6

虽然声明很奇怪。他不想删除单引号吗？为什么每个人都发布删除双引号的答案。

这是我的建议：

result = '"testing","0.8841","642000.0","80.014521","-60.940653","4522126666","1500854400","","1500842014000","name","80.014521","-60.996532","sampledevice","3","name"'

data = result.split("\n")

s = str(data)[2:-2] #Convert to a string, and delete [' and ']
for dd in s.split(','):
    print dd

结果：

"testing"
"0.8841"
"642000.0"
"80.014521"
"-60.940653"
"4522126666"
"1500854400"
""
"1500842014000"
"name"
"80.014521"
"-60.996532"
"sampledevice"
"3"
"name"

从Python中的列表中删除单引号

6 个答案: