Question

我想用其他条件计算表中的行。我在某种程度上有这个，但它不起作用。

$sql = "SELECT
 (SELECT COUNT(name) FROM orders) as total,
  UNION ALL
 (SELECT COUNT(name) FROM orders  WHERE status='1') as ok,
  UNION ALL
 (SELECT COUNT(name) FROM orders  WHERE status='2') as ko";

Answer 1

使用条件聚合：

select count(*) as total, sum(status = 1) as ok, sum(status = 2) as ko
from orders;

注意：这假设status确实存储为数字。不要使用单引号作为数字常量（当你真的打算使用字符串时，请使用它们。）

Answer 2

您可以使用count

table多个simple query的数据

$sql = "SELECT COUNT(name) AS `total`, (SELECT COUNT(name) FROM orders  WHERE status='1') as `second`, (SELECT COUNT(name) FROM orders  WHERE status='2') as `third` FROM orders";

function getWeekDates($date, $start_date, $end_date) {
    $week = date('W', strtotime($date));
    $year = date('Y', strtotime($date));
    $from = date("Y-m-d", strtotime("{$year}-W{$week}+1"));

    if ($from < $start_date)
        $from = $start_date;

    $to = date("Y-m-d", strtotime("{$year}-W{$week}-7"));
    if ($to > $end_date)
        $to = $end_date;

    $array1 = array(
        "ssdate" => $from,
        "eedate" => $to,
    );

    return $array1;
}

$mm = date('m');
$yy = date('y');
$startdate = date($yy . "-" . $mm . "-01");
$current_date = date('Y-m-t');
$ld = cal_days_in_month(CAL_GREGORIAN, $mm, $yy);
$lastday = $yy . '-' . $mm . '-' . $ld;
$start_date = date('Y-m-d', strtotime($startdate));
$end_date = date('Y-m-d', strtotime($lastday));
$end_date1 = date('Y-m-d', strtotime($lastday . " + 7 days"));
$count_week = 0;
$week_array = array();

for ($date = $start_date; $date < $end_date1; $date = date('Y-m-d', strtotime($date . ' + 7 days'))) {
    $getarray = getWeekDates($date, $start_date, $end_date);
    $week_array[] = $getarray;
    $count_week++;
}
echo '<pre>';
print_r($week_array);

了解更多信息as explained here in the FineManual

多表条件下的行数

2 个答案: