Question

字符串time1 =“09-00 AM”;字符串time2 =“07-00 PM”;

String date = 15-09-2017 04:04:33

parseInt()

如何比较time1和。之间存在的日期时间时间2请建议我如何检查这个，我无法分割时间或与日期合并。

为此，我试图在HH中的Date对象中转换time1和time2：mm：SS

Answer 1

使用.after方法比较两个日期查看此link了解更多详情

Answer 2

public static void main(String[] args) {
        try {
            SimpleDateFormat df = new SimpleDateFormat("HH:mm a");
            Date time1 = df.parse("09-00 AM");
            Date time2 = df.parse("07-00 PM");
            Date date = new Date();
            SimpleDateFormat sf = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
            //converts date to required format
            String current = sf.format(date);
            Date currentTime = df.parse(current);
            // TODO COMPARE currentTime with time1 or time2 as per your need

            System.out.println(time1 + "" + time2 +" " + currentTime);
        } catch (ParseException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

如何比较android中两次之间存在的时间

2 个答案: