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在这段代码中,我在同一页面上创建了facebook登录和google登录,例如google.php,google登录工作完美,facebook登录也正常工作,但是当我登录facebook时会出现一些错误。它会显示一些错误,如:
public function login()
{
$userData = array();
if($this->facebook->is_authenticated())
{
$userProfile = $this->facebook->request('get', '/me?fields=id,first_name,last_name,email');
$userData['oauth_provider'] = 'facebook';
$userData['oauth_uid'] = $userProfile['id'];
$userData['firstname'] = $userProfile['first_name'];
$userData['lastname'] = $userProfile['last_name'];
$userData['email'] = $userProfile['email'];
$userData['password'] = rand();
$userID = $this->user->checkUser($userData);
if(!empty($userID))
{
$data['userData'] = $userData;
$this->session->set_userdata('userData',$userData);
}
else
{
$data['userData'] = array();
}
$data['logoutUrl'] = $this->facebook->logout_url();
}
else
{
$fbuser = '';
$data['authUrl'] = $this->facebook->login_url();
}
if($this->session->userdata('loggedIn') == true)
{
redirect('test/profile');
}
if(isset($_GET['code']))
{
$this->google->getAuthenticate();
$gpInfo = $this->google->getUserInfo();
$userData['oauth_provider'] = 'google';
$userData['oauth_uid'] = $gpInfo['id'];
$userData['firstname'] = $gpInfo['given_name'];
$userData['lastname'] = $gpInfo['family_name'];
$userData['email'] = $gpInfo['email'];
$userData['password'] = rand();
$userID = $this->user->checkUser($userData);
$this->session->set_userdata('loggedIn', true);
$this->session->set_userdata('userData', $userData);
redirect('test/profile');
}
$data['loginURL'] = $this->google->loginURL();
$data['student_id'] = $this->session->userdata('student_id');
$this->load->view('header-inside',$data);
$this->load->view('login',$data);
}
我不知道为什么。那么,我该如何解决这个问题呢?请帮帮我。
谢谢
答案 0 :(得分:0)
将Google身份验证和Facebook身份验证的逻辑分开,当您尝试使用Facebook $ _GET ['code']进行身份验证时,此变量会被设置,因为它会导致google身份验证代码,并且会显示错误消息:获取OAuth2访问令牌时出错,消息:'invalid_grant'