我会递归地浏览所有JS文件并缩小它们。但是我必须保留一些JS文件。
我使用dir，findstr和for /f %i in ('dir /b /a-d /s "D:\update" ^| findstr /liv "\admin" ^| findstr /ile ".js" ^| findstr /vile "-min.js" ^| findstr /vile ".min.js"') do echo %i
的组合获得了很多成功。但是当我想忽略已经缩小的文件（以“-min.js”结尾的文件）时，FINDSTR命令就崩溃了。
这是我用过的命令：
FINDSTR: /. ignored
FINDSTR: /j ignored
FINDSTR: Bad command line
FINDSTR: Write error
FINDSTR: Write error
FINDSTR: Write error
FINDSTR: Write error
出现以下错误：
findstr /vile "-min.js"问题肯定是使用[
{
"id": 19,
"subSpecialtyId": 1,
"institutionAccreditationApplicationId": 13,
"subSpecialtyName": "Chromatography",
"exams": [
{
"id": 1001,
"name": "Part 1",
"departmentId": 0,
"designation": null,
"index": 4,
"statuses": [
{
"id": 1,
"name": "Full",
"departmentId": 0,
"designation": null
},
{
"id": 2,
"name": "Partial",
"departmentId": 0,
"designation": null
},
{
"id": 3,
"name": "Denied",
"departmentId": 0,
"designation": null
},
{
"id": 1002,
"name": "Full for Part 1",
"departmentId": 0,
"designation": null
}
]
},
{
"id": 1002,
"name": "Part II",
"departmentId": 0,
"designation": null,
"index": 5,
"statuses": [
{
"id": 1,
"name": "Full",
"departmentId": 0,
"designation": null
},
{
"id": 2,
"name": "Partial",
"departmentId": 0,
"designation": null
},
{
"id": 3,
"name": "Denied",
"departmentId": 0,
"designation": null
},
{
"id": 1002,
"name": "Full for Part 1",
"departmentId": 0,
"designation": null
}
]
}
]
},
{
"id": 20,
"subSpecialtyId": 4,
"institutionAccreditationApplicationId": 13,
"subSpecialtyName": "Sub Specialty F",
"exams": [
{
"id": 1001,
"name": "Part 1",
"departmentId": 0,
"designation": null,
"index": 4,
"statuses": [
{
"id": 1,
"name": "Full",
"departmentId": 0,
"designation": null
},
{
"id": 2,
"name": "Partial",
"departmentId": 0,
"designation": null
},
{
"id": 3,
"name": "Denied",
"departmentId": 0,
"designation": null
},
{
"id": 1002,
"name": "Full for Part 1",
"departmentId": 0,
"designation": null
}
]
},
{
"id": 1002,
"name": "Part II",
"departmentId": 0,
"designation": null,
"index": 5,
"statuses": [
{
"id": 1,
"name": "Full",
"departmentId": 0,
"designation": null
},
{
"id": 2,
"name": "Partial",
"departmentId": 0,
"designation": null
},
{
"id": 3,
"name": "Denied",
"departmentId": 0,
"designation": null
},
{
"id": 1002,
"name": "Full for Part 1",
"departmentId": 0,
"designation": null
}
]
}
]
}
]
子句但是我不知道为什么连字符会导致问题，因为我使用的是/ l（文字）标志。
答案 0 :(得分：3)
处理class(gd)
[1] "grouped_df" "tbl_df" "tbl" "data.frame"
class(meansummpas)
[1] "data.frame"
可执行文件参数的C运行时遵循一组规则。其中一条规则是使用双引号来保护单独参数中的空格/特殊字符，但是，一旦命令行被标记化并且标识了参数，就会在将单独的参数传递给主代码之前删除引号。
这意味着这个命令
findstr将在可执行文件中处理为
findstr /vile "-min.js"
，并且，argv[0] = findstr
argv[1] = /vile
argv[2] = -min.js
接受参数分组（如findstr中所述），但它也允许以/vile或/开头的参数，-接受-m，-i，-n次切换（全部有效），但会忽略-s和-.（未知）。
命令行不好，因为在参数中找不到搜索字符串。
记录在案的（-j）解决方案是使用findstr /?语法
/c:"stringToMatch"或者您可以使用转义字符，因此findstr /vile /c:"-min.js"
不会作为选项参数初始字符处理
-