Question

我从gmail标头获得了这种json数据。我怎样才能解析它以获得android中“传递到”和“收到”的值。提前谢谢。

[
    {"name":"Delivered-To","value":"ayuka******l@gmail.com"},

    {"name":"Received","value":"by 10.140.22.233 with SMTP id 96csp129737qgn;        Tue, 12 Sep 2017 14:11:47 -0700 (PDT)"}, 

    {"name":"X-Google-Smtp-Source","value":"ADKCNb5EL+VcU9VEZ4HxoicjzSkTx8DxijwG+0LOR+My5P4fQoiAwNEY8LYBEN/kCq+ITzM43nDg"},

    {"name":"X-Received","value":"by 10.129.183.31 with SMTP id v31mr14525436ywh.24.1505250707382;        Tue, 12 Sep 2017 14:11:47 -0700 (PDT)"}   
]

Answer 1

您只需要通过索引获取JSON对象，然后获取json字段＆＃34; name＆＃34;在这种情况下

JSONArray yourData = new JSONArray(jsonFromGmail); // Put your data inside a JSONArray  
String name = ""; 

try {
   for (int i = 0; i < yourData.length(); i++) {//Loop through your JSON array
         JSONObject jsonobj = null;
         jsonobj = yourData.getJSONObject(i); //Get JSONObjects by index
         System.out.println("name : " + i + " = " + jsonobj.getString("name"));
         name = jsonobj.getString("name");
         // Do whatever you want with the string
     }
 } catch (JSONException e) {
     e.printStackTrace();
 }

希望有所帮助

Answer 2

这可以使用Gson（有关安装说明和文档，请参阅https://github.com/google/gson）：

    String json = "[ {\"name\":\"Delivered-To\",\"value\":\"ayuka******l@gmail.com\"}, {\"name\":\"Received\",\"value\":\"by 10.140.22.233 with SMTP id 96csp129737qgn;        Tue, 12 Sep 2017 14:11:47 -0700 (PDT)\"}, {\"name\":\"X-Google-Smtp-Source\",\"value\":\"ADKCNb5EL+VcU9VEZ4HxoicjzSkTx8DxijwG+0LOR+My5P4fQoiAwNEY8LYBEN/kCq+ITzM43nDg\"}, {\"name\":\"X-Received\",\"value\":\"by 10.129.183.31 with SMTP id v31mr14525436ywh.24.1505250707382;        Tue, 12 Sep 2017 14:11:47 -0700 (PDT)\"}]";

    // parse the JSON string as an array
    JsonArray array = new Gson().fromJson(json, JsonArray.class);
    String deliveredTo = "";
    String received = "";

    // iterate through the items of the array
    for (int i = 0; i < array.size(); i++) {
        // parse each item as a JSON object, extract name and value from it
        JsonObject element = array.get(i).getAsJsonObject();
        String name = element.get("name").getAsString();
        String value = element.get("value").getAsString();
            // look for the relevant fields in name; if we found them, set the according values
            if (name.equals("Delivered-To")) {
                deliveredTo = value;
            } else if (name.equals("Received")) {
                received = value;
            }
    }
    System.out.println("Delivered to: " + deliveredTo);
    System.out.println("Received: " + received);

在你将它用于制作之前，你当然应该添加一些关于Json有效性的检查，而不是像我在这里做的那样假设（例如：name和value存在于每个项目中数组）。

Answer 3

工作正常。

JSONArray emailHeaderObj = null;
    String deliveredTo = " ";
    String received = " ";
    String Subject = " ";
    String from = "";
    try {
        emailHeaderObj = new JSONArray(emailHeaderString);

        for (int i = 0; i < emailHeaderObj.length(); i++) {

            JSONObject element = emailHeaderObj.getJSONObject(i);
            String name = element.getString("name");
            String value = element.getString("value");

            switch(name){
                case "Date":
                    received = value;
                    break;
                case "Subject":
                    Subject = value;
                    break;
                case "From":
                    from = value;
                    break;
            }
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }

从电子邮件标题中解析JSON

3 个答案: