Question

目前我有一个类似的列表：

CADisplayLink

当我添加和删除类时，我宁愿不必维护长列表。有没有办法在.net core 2中找到并实例化扩展另一个类的所有类？

提前感谢您的帮助。

Answer 1

是的，请参阅Getting all types that implement an interface

fn call(&self, req: hyper::server::Request) -> Self::Future {
    let mut response: Response = Response::new();

    match (req.method(), req.path()) {
        (&Method::Post, "/assets") => {
            if let Some(len) = req.headers().get::<ContentLength>() {
                response.headers_mut().set(len.clone());
            }

            response = response.with_body("req.body()");
        }
        _ => {
            response.set_status(StatusCode::NotFound);
        }
    };

    futures::future::ok(response)
}

如果它们都具有无参数构造函数，则可以使用Activator.CreateInstance创建实例

var type = typeof(Algo);
var types = AppDomain.CurrentDomain.GetAssemblies()
    .SelectMany(s => s.GetTypes())
    .Where(p => type.IsAssignableFrom(p));

实例化大量的类

1 个答案: