Question

我有一个像这样的对象数组：

var array = [
    {minutes: 45, hours: 4, meridiem: "PM"},
    {minutes: 00, hours: 8, meridiem: "AM"},
    {minutes: 45, hours: 8, meridiem: "AM"},
    {minutes: 30, hours: 3, meridiem: "PM"},
    {minutes: 15, hours: 11, meridiem: "AM"},
    {minutes: 00, hours: 1, meridiem: "PM"}
]

基本上我需要按时间排序，最早的第一个。因此，如果小时和经度相等，那么按AM / PM然后按小时计算，然后按分钟计算。

这是我尝试过的

this.currentTours.sort(function(a,b) {
  if (a.meridiem != b.meridiem) {
    return 1
  }
  if ((a.dateR.meridiem == b.dateR.meridiem) && a.dateR.hours != 
  b.dateR.hours) {
    return 1
  }
  if (((a.dateR.meridiem == b.dateR.meridiem) && a.dateR.hours != 
  b.dateR.hours) && a.dateR.minutes != b.dateR.minutes) {
    return 1
  }
  return a.dateR.meridiem - b.dateR.meridiem
})

越过1层属性就是我被困住的地方。

Answer 1

您可以使用链式方法进行嵌套排序，并对12 am or pm进行小时校正。这些值被解释为零。

(a.hours < 12) * a.hours

var array = [{ minutes: 45, hours: 4, meridiem: "PM" }, { minutes: 00, hours: 8, meridiem: "AM" }, { minutes: 45, hours: 8, meridiem: "AM" }, { minutes: 30, hours: 3, meridiem: "PM" }, { minutes: 15, hours: 11, meridiem: "AM" }, { minutes: 00, hours: 1, meridiem: "PM" }, { minutes: 00, hours: 12, meridiem: "PM" },{ minutes: 00, hours: 12, meridiem: "AM" }];

array.sort(function (a, b) {
    return (b.meridiem === 'AM') - (a.meridiem === 'AM')
        || (a.hours < 12) * a.hours - (b.hours < 12) * b.hours
        || a.minutes - b.minutes;
});

console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

您可以在if方法中使用简单的Array.prototype.sort语句来考虑多个属性。

如果两个属性完全相同，请咨询下一个最重要的属性以打破这种关系。

var array = [
  { minutes: 45, hours: 4, meridiem: "PM" },
  { minutes: 00, hours: 8, meridiem: "AM" },
  { minutes: 45, hours: 8, meridiem: "AM" },
  { minutes: 30, hours: 3, meridiem: "PM" },
  { minutes: 15, hours: 11, meridiem: "AM" },
  { minutes: 00, hours: 1, meridiem: "PM" }
];

array.sort(function(a, b) {
  if (a.meridiem !== b.meridiem)
    return a.meridiem === 'AM' ? -1 : 1;
  
  if (a.hours !== b.hours)
    return a.hours - b.hours;
  
  return a.minutes - b.minutes
});

console.log(array);

按属性排序对象数组（多级）

2 个答案: