Question

我试图在Python3中模仿http://www.hanewin.net/encrypt/aes/aes-test.htm的Rijndael（AES）加密。

具体来说，当我使用以下输入时：

Key in hex = AAAABBBBCCCCDDDDEEEEFFFF00001111 
Plaintext in hex = 11112222333344445555666677778888

我希望输出为：

Ciphertext in hex = ec151e51fc722c06073928d17fa4f6da

通过查看网页的源代码，它正在使用ECB。我已经安装了PyCrypto并按照加密示例进行了加密，这就是我所得到的：

>>> from Crypto.Cipher import AES
>>>
>>> KEY = 'AAAABBBBCCCCDDDDEEEEFFFF00001111'
>>> rijn = AES.new(KEY, AES.MODE_ECB)
>>> plaintext = '11112222333344445555666677778888'
>>> ciphertext = rijn.encrypt(plaintext)
>>> ciphertext
b'\xf8Gy\x17\x85$\xf4?\xd3}\x91\xa1\xad\xab\xa1\x07g\xf7P\xd4:\x7f\xc0\x18m)\rTu,\xd0\xa2'

所以我的密文就是长二进制字符串（如果这是正确的术语）。假设所有设置都是正确的，它应该相当于ec151e51fc722c06073928d17fa4f6da。如何将b'\xf8Gy\x17\x85$\xf4?\xd3}\x91\xa1\xad\xab\xa1\x07g\xf7P\xd4:\x7f\xc0\x18m)\rTu,\xd0\xa2'转换为ec151e51fc722c06073928d17fa4f6da？

更新：根据Jon在评论中提出的建议，我已经导入了binascci，现在我得到了以下输出：

>>> import binascii
>>> 
>>> binascii.hexlify(ciphertext)
b'f84779178524f43fd37d91a1adaba10767f750d43a7fc0186d290d54752cd0a2'

所以它可能仍然是我有正确的密码，但转换中有些不同。以下是网页源代码的摘录：

theForm.ciphertext.value = byteArrayToHex(rijndaelEncrypt(pt, key, "ECB"));


// This function takes an array of bytes (byteArray) and converts them
// to a hexadecimal string. Array element 0 is found at the beginning of 
// the resulting string, high nibble first. Consecutive elements follow
// similarly, for example [16, 255] --> "10ff". The function returns a 
// string.

function byteArrayToHex(byteArray) {
  var result = "";
  if (!byteArray)
    return;
  for (var i=0; i<byteArray.length; i++)
    result += ((byteArray[i]<16) ? "0" : "") + byteArray[i].toString(16);

  return result;
}

Answer 1

如上所述，以下是评论者帮助达成的答案：

>>> from Crypto.Cipher import AES
>>> import binascii
>>> KEY = binascii.unhexlify('AAAABBBBCCCCDDDDEEEEFFFF00001111')
>>> plaintext = binascii.unhexlify('11112222333344445555666677778888')
>>> rijn = AES.new(KEY, AES.MODE_ECB)
>>> ciphertext = rijn.encrypt(plaintext)
>>> binascii.hexlify(ciphertext)
b'ec151e51fc722c06073928d17fa4f6da'
>>> print(binascii.hexlify(ciphertext).decode('utf-8'))
ec151e51fc722c06073928d17fa4f6da

Python Rijndael加密

1 个答案: