我有一个JSON数组。我尝试转换嵌套的分层树。但它没有用。我需要使用这个JSON的分层树。
这是我的数据:
[{
"_id" : "59b65ee33af7a11a3e3486c2",
"C_TITLE" : "Sweet and Snacks",
"C_PARENT" : "0",
"C_ICON" : "",
"C_IMAGE" : "59b65ee33af7a11a3e3486c2_sweets.jpg",
"C_STATUS" : "Active"
}
{
"_id" : "59b663d709da571dc3d79f49",
"C_TITLE" : "Groceries",
"C_PARENT" : "0",
"C_ICON" : "",
"C_IMAGE" : "59b663d709da571dc3d79f49_grocery.jpg",
"C_STATUS" : "Active"
},
{
"_id" : "59b6648209da571dc3d79f4a",
"C_TITLE" : "Dals & Pulses",
"C_PARENT" : "59b663d709da571dc3d79f49",
"C_ICON" : "",
"C_IMAGE" : "59b6648209da571dc3d79f4a_dals.jpg",
"C_STATUS" : "Active"
},
{
"_id" : "59b6657509da571dc3d79f4c",
"C_TITLE" : "Rice & Rice products",
"C_PARENT" : "59b663d709da571dc3d79f49",
"C_ICON" : "",
"C_IMAGE" : "59b6657509da571dc3d79f4c_rice.jpg",
"C_STATUS" : "Active"
}]
我需要这样的输出
[
{
" _id" : "59b65ee33af7a11a3e3486c2",
"C_TITLE" : "Sweet and Snacks",
"C_PARENT" : "0",
"C_ICON" : "",
"C_IMAGE" : "59b65ee33af7a11a3e3486c2_sweets.jpg",
"C_STATUS" : "Active",
children:[]
}
]
基于检查C_PARENT和_id。
答案 0 :(得分:0)
基本上,您需要而不是
o[a.id]
此
o[a._id]
因为您的数据有_id
作为密钥ID。
另一个问题是与root
的严格比较,你需要一个字符串作为值'0'
,因为这是你拥有的值。
var data = [{ _id: "59b65ee33af7a11a3e3486c2", C_TITLE: "Sweet and Snacks", C_PARENT: "0", C_ICON: "", C_IMAGE: "59b65ee33af7a11a3e3486c2_sweets.jpg", C_STATUS: "Active" }, { _id: "59b663d709da571dc3d79f49", C_TITLE: "Groceries", C_PARENT: "0", C_ICON: "", C_IMAGE: "59b663d709da571dc3d79f49_grocery.jpg", C_STATUS: "Active" }, { _id: "59b6648209da571dc3d79f4a", C_TITLE: "Dals & Pulses", C_PARENT: "59b663d709da571dc3d79f49", C_ICON: "", C_IMAGE: "59b6648209da571dc3d79f4a_dals.jpg", C_STATUS: "Active" }, { _id: "59b6657509da571dc3d79f4c", C_TITLE: "Rice & Rice products", C_PARENT: "59b663d709da571dc3d79f49", C_ICON: "", C_IMAGE: "59b6657509da571dc3d79f4c_rice.jpg", C_STATUS: "Active" }],
result = function (array, root) {
var r = [], o = {};
array.forEach(function (a) {
a.children = o[a._id] && o[a._id].children; // change to a._id
o[a._id] = a; // change to a._id
if (a.C_PARENT === root) { // strict comparison!
r.push(a);
return;
}
o[a.C_PARENT] = o[a.C_PARENT] || {};
o[a.C_PARENT].children = o[a.C_PARENT].children || [];
o[a.C_PARENT].children.push(a);
});
return r;
}(data, "0"); // "0" as root
console.log(result);

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