Question

我有这个声明，它返回2个不同的计数，我正在尝试加入这个月的计数。以下是我当前的陈述，我知道我的问题是COUNT（SecondColl。*）作为第二张桌子的STRAFT。我可以这样做吗？

WITH cte as(
    SELECT * FROM K1
    UNION ALL
    SELECT * FROM K2
    UNION ALL
    SELECT * FROM K3
    UNION ALL
    SELECT * FROM K4
), FirstColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count
            from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'STR'
), SecondColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count
            from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'NCD'
)
SELECT MONTH(ED) as STRMnth, COUNT(*) as STRRFT , COUNT(SecondColl.*) as STRAFT
FROM FirstColl
inner join SecondColl where MONTH(ED) = SecondColl.MONTH(ED)
group by MONTH(ED)
order by STRMnth asc

Answer 1

试试这个：

WITH cte as(
    SELECT * FROM K1
    UNION ALL
    SELECT * FROM K2
    UNION ALL
    SELECT * FROM K3
    UNION ALL
    SELECT * FROM K4
), FirstColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count
            from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'STR'
), SecondColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count
            from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'NCD'
)
select 
    a.STRMnth, a.cnt1 as STRRFT, b.cnt2 as STRAFT
from 
    (select month(ED) as STRMnth, count(*) as cnt1 from FirstColl group by month(ED)) a
    left join 
    (select month(ED) as STRMnth, count(*) as cnt2 from SecondColl group by month(ED)) b
        on a.STRMnth = b.STRMnth
order by a.STRMnth asc

<强> UPDATE1：

WITH cte as(
        SELECT * FROM K1
        UNION ALL
        SELECT * FROM K2
        UNION ALL
        SELECT * FROM K3
        UNION ALL
        SELECT * FROM K4
    ), FirstColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count
                from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'STR'
    ), SecondColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count
                from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'NCD'
    ), ThirdColl as (SELECT Distinct ED, DP, RN FROM cte WHERE DT = 'STR')
    select 
        a.STRMnth, a.cnt1 as STRRFT, b.cnt2 as STRAFT
    from 
        (select month(ED) as STRMnth, count(*) as cnt1 from FirstColl group by month(ED)) a
        left join 
        (select month(ED) as STRMnth, count(*) as cnt2 from SecondColl group by month(ED)) b
            on a.STRMnth = b.STRMnth
        left join 
        (select month(ED) as STRMnth, count(*) as cnt3 from ThirdColl group by month(ED)) c
            on a.STRMnth = c.STRMnth
    order by a.STRMnth asc

<强> UPDATE2：

WITH cte as(
        SELECT * FROM K1
        UNION ALL
        SELECT * FROM K2
        UNION ALL
        SELECT * FROM K3
        UNION ALL
        SELECT * FROM K4
    ), FirstColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count
                from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'STR'
    ), SecondColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count
                from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'NCD'
    ), ThirdColl as (SELECT distinct ED, DP, RN FROM K1 WHERE Defect_Type = 'STR')
    select 
        a.STRMnth, a.cnt1 as STRRFT, b.cnt2 as STRAFT
    from 
        (select month(ED) as STRMnth, count(*) as cnt1 from FirstColl group by month(ED)) a
        left join 
        (select month(ED) as STRMnth, count(*) as cnt2 from SecondColl group by month(ED)) b
            on a.STRMnth = b.STRMnth
        left join 
        (select month(ED) as STRMnth, count(*) as cnt3 from ThirdColl group by month(ED)) c
            on a.STRMnth = c.STRMnth
    order by a.STRMnth asc

sql join计数

1 个答案: