Question

从openfire rest api获取用户实体时收到以下错误消息。（我用openfire Restapi端点封装了我的Api端点。）

“错误”：“内部服务器错误”， “exception”：“org.springframework.http.converter.HttpMessageNotWritableException”， “message”：“无法编写JSON：没有为类java.io.ByteArrayInputStream找到序列化程序，也没有发现创建BeanSerializer的属性（为了避免异常，请禁用SerializationFeature.FAIL_ON_EMPTY_BEANS）;嵌套异常是com.fasterxml.jackson.databind.JsonMappingException ：找不到类java.io.ByteArrayInputStream的序列化程序，并且没有发现创建BeanSerializer的属性（为了避免异常，请禁用SerializationFeature.FAIL_ON_EMPTY_BEANS）（通过引用链：com.mashape.unirest.http.HttpResponse [\“rawBody \”]） ” “path”：“/ usersInfo / user2”

代码如下。

String  host ="http://abdul01anpi01:9090" ;
String userEndPoint = "/plugins/restapi/v1/users" ;
String apiURL = host+userEndPoint ;
HttpResponse<JsonNode> response =null;

response = Unirest.get(apiURL +"/{username}").header("accept", "application/json").header("Content-Type", "application/json").routeParam("username",String.valueOf(username)).asJson();

响应的预期输出如下。

{
    "username": "user2",
    "name": "user2",
    "properties": null
}

请告知，任何帮助表示赞赏。

Answer 1

张贴者找到了解决方案，并将其张贴在评论中。既然已经过去了几年，所以我认为可以将它复制为实际答案：

public function deleteProductImageName($id) {
        if(Auth::check()) {

            $products = Product::where('id', $id)->first();

            foreach($products as $p) {
                if(($products->user_id == Auth::user()->id) && ($products->id == $id)) {
                  $product = Product::where('user_id', Auth::user()->id)
                        ->where('id', $id)->first();

                     $filename_index = $product->filename;

                echo $filename_index; '<br/>';
                echo $filename_index . '[' . $index . ']';
                }
            }
        } else {
            Session::flash("message", "OOPS! You dont have permission to delete the items. Please login first.");
            return redirect("/register-user");

        }
    }

让我为正在设置为@Bean public MappingJackson2HttpMessageConverter mappingJackson2HttpMessageConverter() { ObjectMapper mapper = new ObjectMapper(); mapper.configure(SerializationFeature.FAIL_ON_EMPTY_BEANS, false); MappingJackson2HttpMessageConverter converter = new MappingJackson2HttpMessageConverter(mapper); return converter; }的标志添加描述：

false

Answer 2

它有效，添加一个ResourceHttpMessageConverter！

@Configuration
public class EirExceptionConfig extends WebMvcConfigurerAdapter {
    @Autowired
    ObjectMapper objectMapper;

    @Override
    public void configureMessageConverters(List<HttpMessageConverter<?>> converters) {
        SimpleModule simpleModule = new SimpleModule();
        simpleModule.addSerializer(EirException.class, new EirExceptionJackson2Serializer());
        objectMapper.registerModule(simpleModule);
        MappingJackson2HttpMessageConverter converter = new MappingJackson2HttpMessageConverter(objectMapper);
        converters.add(new ResourceHttpMessageConverter());
        converters.add(converter);
    }
}

Answer 3

解决此问题的另一种方法是忽略返回类型为ByteArrayInputStream的属性，例如，您可以修饰此类：

class Frodo {
    private bytes[] value;
    public Frodo(bytes[] value) {
        this.value = value;
    }

    public ByteArrayInputStream getFoo() throws IOException {
        return new ByteArrayInputStream(value());
    }

    public void setFoo(ByteArrayInputStream streamData) {
        // set value from streamData
    }
}

像这样：

@JsonIgnoreProperties(value = { "foo" })
class Frodo {
    private bytes[] value;
    public Frodo(bytes[] value) {
        this.value = value;
    }

    public ByteArrayInputStream getFoo() throws IOException {
        return new ByteArrayInputStream(value());
    }

    public void setFoo(ByteArrayInputStream streamData) {
        // set value from streamData
    }
}

您还可以忽略多个属性：@JsonIgnoreProperties(value = { "foo", "anotherValue" })

没有为类java.io.ByteArrayInputStream找到序列化程序

3 个答案: