Question

我有一个具有以下结构的字典：

count = 0 leng = 0 i = 0 for key1,key2 in range(1,len(bigrams)): count = count +1 leng = leng + (bigrams.get((key1,key2),0)) print(count) print(leng)

我想在字典中计算次数＆＃39; key1＆＃39;例如，显示为键元组中的第一个单词。

我开始编写下面提到的代码，但无法进一步思考：

<!DOCTYPE html>
<html lang="en">

    <head>
        <meta charset="utf-8"/>
        <title> Competition Organizer </title>
        <link rel="stylesheet" href="main.css">
    </head>

    <body>
        <ul> 
            <li><a href="">Log Out</a></li>
            <li><a>Notification</a></li>
            <li><a href="Report.html">Generate Report</a></li>
            <li><a href="Admin.html">Home</a></li>
            <li style="float:left;color:white;">Competition Management</li>
        </ul>
        <form action="http://localhost/GCSweb/add.php" method="POST">
            <div>
                <br>
                <br>
                <br>

                <label><b>Competition Name</b></label>
                <input type="text" placeholder="Enter Competiton Name" name="compname" required>

                <label><b>Competition Mentor</b></label>
                <input type="text" placeholder="Enter Competiton Mentor Name" name="compmenname" required>

                <label><b>Competiton Description</b></label>
                <textarea rows="20" cols="50" name="compdescription" form="CompForm" placeholder="Enter Description Here..." required></textarea>

                <br>

                <input type="submit" value="Submit" name="submit">
            </div>
        </form>

    </body>

</html>

有关我应该如何进行的任何建议？

Answer 1

from collections import defaultdict

der = {('key1','key2'): 50, ('key3','key4'): 70, ('key1','key5'): 90}

b = defaultdict(int)
for item, ler in der:
    b[item] += 1
print b         ## defaultdict(int, {'key1': 2, 'key3': 1})
print b['key1'] ## [2]

Python tuple operations and count

Answer 2

我使用带有生成器表达式的sum()迭代键，依次测试每个键：

bigrams = {('key1','key2'): 50, ('key3','key4'): 70, ('key1','key5'): 90}

def number_of_times_key_appears_as_first_word(key, dictionary):
    return sum(k[0] == key for k in dictionary)

assert number_of_times_key_appears_as_first_word('key1', bigrams) == 2
assert number_of_times_key_appears_as_first_word('key3', bigrams) == 1
assert number_of_times_key_appears_as_first_word('key2', bigrams) == 0

Answer 3

您可以使用collections.Counter计算密钥的每个部分，如下所示：

from collections import Counter
dic = {('key1','key2'): 50, ('key3','key4'): 70, ('key1','key5'): 90}
keys_0 = Counter(key[0] for key in dic.keys())
keys_1 = Counter(key[1] for key in dic.keys())

# keys_0 = Counter({'key1': 2, 'key3': 1})
# keys_1 = Counter({'key2': 1, 'key4': 1, 'key5': 1})

如果需要，可以使用dict(Counter(...))

键入强制转换计数器对象

Answer 4

下面给出了所需的计数：

dict1 = {('key1','key2'): 50, ('key3','key4'): 70, ('key1','key5'): 90, ('key3','key1'): 90}
count = 0
for keys in dict1.keys():
    if 'key1' in keys:
        if (keys[0] == 'key1'):
            count = count + 1
print count

检查一个元组的一个键在dict中重复多少次？

4 个答案: