Question

目前，每个玩家只有一个转弯，并且永远不会显示游戏的赢家。需要对这个主要功能进行哪些更改才能让每个玩家完全三次？

def main():
    display_welcome()    #1
    number_of_turns = 3
    score_player1 = 0
    score_player2 = 0
    name_player1 = "Olivia"
    name_player2 = "Ned"
    turn_num = 1
    first_player_num = random.randrange(1, number_of_turns + 1)

    if first_player_num == 2:
        temp = name_player1
        name_player1 = name_player2
        name_player2 = temp

    score1 = have_one_turn(turn_num, name_player1)
    score2 = have_one_turn(turn_num, name_player2)

    score_player1 = score_player1 + score1
    score_player2 = score_player2 + score2

    if turn_num < number_of_turns:
        display_turn_results(name_player1, score_player1, name_player2, score_player2, False)     #10
    else:
        display_turn_results(name_player1, score_player1, name_player2, score_player2, True)

Answer 1

尝试以下代码::

def main():
    display_welcome()    #1
    number_of_turns = 3
    score_player1 = score_player2 = 0
    name_player1 = "Olivia"
    name_player2 = "Ned"
    first_player_num = random.randrange(1, 2)
    if first_player_num == 2:
        temp = name_player1
        name_player1 = name_player2
        name_player2 = temp
    for turn_num in xrange(3):
        score1 = have_one_turn(turn_num, name_player1)
        score2 = have_one_turn(turn_num, name_player2)
        score_player1 = score_player1 + score1
        score_player2 = score_player2 + score2

        if turn_num+1 < number_of_turns:
            display_turn_results(name_player1, score_player1, 
                                 name_player2, score_player2, False)     #10
        else:
            display_turn_results(name_player1, score_player1, 
                                 name_player2, score_player2, True)

如果main函数的一部分可以分成另一部分，则可以使用递归函数调用。

def main():
#display function and selecting player to play first.
    game(score1, score2, name_player1, name_player2)

游戏功能可以称为递归

def game(score1, score2, name_player1, name_player2, turn_num=1):
    #calculating score
    number_of_turns = 3 
    turn_num = turn_num+1
    if turn_num < number_of_turns:
        display_turn_results(name_player1, score_player1, 
                             name_player2, score_player2, False)
        game(score_player1, score_player2,  name_player1,
             name_player2, turn_num)
    else:
        display_turn_results(name_player1, score_player1, 
                             name_player2, score_player2, True)

需要对主要功能进行哪些更改才能使每个玩家正好进行三次转弯？

1 个答案: