Question

好吧，我已经编辑了一些代码，所以现在的问题是它如何计算正确的最终总数？我正在处理常规服务，我希望它先减去50分钟的免费分钟，然后添加用户过度使用的额外分钟数，然后将额外的分钟数乘以$ 0.20并将其计入最终总数。如果我有任何更多的错误，请告诉我。我知道我犯了很多错误，对不起！我有一个项目要做，这是请求的功能列表：

提示用户输入帐号，服务代码以及使用服务的分钟数。
- 常规：值为“R”和“r”：
  - $ 10.00 /月
  - 前50分钟是免费的
  - 充电超过50分钟。是每分钟0.20美元。
- 高级：值为“P”和“p”：
  
  $ 25.00 /月加：
  - 6至18分钟前75分钟的通话是免费的，之后是每分钟0.10美元
  - 18至6分钟前100分钟的通话是免费的，之后是每分钟0.05美元
如果使用任何其他字符，则显示错误消息
计算总额并打印帐单（显示出来）

这是我的代码：

#include <iostream>

using namespace std;
int main()
{
// VARIABLES //
int accnum, minnum, minnumm;
double total, finaltotal, grandtotal, finaltotall;
char scode;

cout << "Hello, thank you for paying your phone bill." << ends;
cout << endl;
cout << endl;

cout << "Please enter your account number: ";
cin >> accnum ; //Enter some number

cout << "Please enter your service code (r as regular service or p for premium service): ";
cin >> scode ;  //Enter R or r for regular service and P or p for premium service

        ////////////// THIS IS FOR REGULAR SERVICE //////////////

if (scode == 'R' || scode == 'r') {     // Values for Regular service
    cout << "This service provides 50 minutes for phone calls for 50 minutes for free for $10.00 a month, and charge $0.20 every minute over 50 minutes." << endl;
    cout << "How many minutes have you used up?: ";
    cin >> minnum;
    if (minnum > 50) {
        total = minnum * .20;
        finaltotal = total + 10;
        cout << "You have made phone calls over 50 minutes, your total will be " << finaltotal << "." << endl;
        cout << "Your account number is " << accnum << " , with a Regular service. You have used " << minnum << "/50 minutes. Your total is $" << finaltotal << " . Thank you for your time." << endl;    //Displays the acc. #, type of service, # of min the phone service used, and amount due from user
        cout << endl;
    } else {
        cout << "You have not made phone calls over 50 minutes, your total will be $" << finaltotal << "." << endl;
        cout << "Your account number is " << accnum << " , with a Regular service. You have used " << minnum << "/50 minutes. Your total is $" << finaltotal << " . Thank you for your time." << endl; //Displays the acc. #, type of service, # of min the phone service used, and amount due from user
    }

       ////////////// THIS IS FOR PREMIUM SERVICE //////////////

} else if (scode == 'P' || scode == 'p') {  //Values for Premium service
    cout << "This service provides your first 75 minutes phone calls from 6:00 - 18:00, and charge $0.10 for every minute over. Your first 100 minutes for phone calls from 18:00 - 6:00 are free, and charge $0.05 for every minute over." << endl;
    cout << "How many minutes have you used up between 6:00 - 18:00? ";    //Time between 6am - 6pm
    cin >> minnumm;
        if (minnumm > 75) {                  //If # of minutes is over 75
            total = minnumm * .10;           //Then it multiplies total * $.10
            finaltotall = total + 25;   //Then adds the $10/month
            cout << "You have made phone calls over 75 minutes, your total will be $" << finaltotall << "." << endl;
        } else {
            cout << "How many minutes have you used up between 18:00 - 6:00? ";  }   //Time between 6pm - 6am
            cin >> minnum;
        if (minnum > 100) {                 //If # of minutes is over 100
            total = minnum * .05;           //Then it multiplies total * $.05
            finaltotal = total + 25;
            //Then adds the $25/month
            cout << "You have made phone calls over 100 minutes, your total will be $" << finaltotal << "." << endl;

            grandtotal = finaltotall + finaltotal;  //Calculates both the 6am-6pm and 6pm-6am totals together
            cout << "Your account number is " << accnum << " , with a Premium service. You have used " << minnumm << "/75 minutes from 6:00-18:00. You have used" << minnum << "/100 from 18:00-6:00. Your total is $" << grandtotal << " . Thank you for your time." << endl; //Displays the acc. #, type of service, # of min the phone service used, and amount due from user
        } else {
            cout << "You have not made phone calls over 100 minutes, your total will be $" << finaltotal << "." << endl;
            cout << "Your account number is " << accnum << " , with a Premium service. You have used " << minnumm << "/75 minutes from 6:00-18:00. You have used " << minnum << "/100 from 18:00-6:00. Your total is " << grandtotal << " . Thank you for your time." << endl;
            cout << endl;
            cout << endl; } //Displays the acc. #, type of service, # of min the phone service used, and amount due from user

        ////////////// THIS IS IF THEY TYPED IN ANY LETTER OTHER THAN R, r, P, p //////////////

} else {        //If user doesn't type P or R, then this is error message
    cout << "Sorry, that service does not exist. Please try again." << endl;
    cout << endl; }


system("pause");
return 0;

}

Answer 1

据我所知（后续答案中的人可能会发现更多错误），明显的问题是您使用了 AND 运算符而不是 OR 运营商。

本声明：

class Test
{
    Test()
    {
        super();
    }
    public static void main(String[] args)
    {
        Test t = new Test();
    }
}

应该是：

if (scode == 'R' && scode == 'r') {     // Values for Regular service

同样，这句话：

if (scode == 'R' || scode == 'r') {     // Values for Regular service

应该是：

if (scode == 'P' && scode == 'p') {  //Values for Premium service

变量不能同时匹配两个不同的值，因此在使用if (scode == 'P' || scode == 'p') { //Values for Premium service而不是if时，永远不会输入&&块。

电话账单项目：C ++

1 个答案: