基于单选按钮选择PHP更新或删除SQL行

Question

我尝试使用PHP根据单选按钮的值更新/删除SQL行。

我的代码如下所示，到目前为止，当我点击提交按钮时 - 它什么也没做！

<form method="post" action="?action">
  <?php
  $stmt = $pdo->query('SELECT * FROM reviews WHERE Approved="0" ORDER BY id DESC');

  while ($result= $stmt->fetch(PDO::FETCH_ASSOC)) { 
  $reviewtitle= $result['Title'];
  $rating= $result['Rating'];
  $name= $result['Name'];
  $date= $result['Date'];
  $review= $result['Review'];
  $ID= $result['ID'];
  $counter = ++$counter;
  ?>

  <br>
  <?php echo $reviewtitle; ?><br>
  <?php echo $rating; ?>
  <br>
  <?php echo $name; ?><br>
  <?php echo $review; ?>
  <p>Posted: <?php echo $date; ?></p>
  <p>Review ID: <input type="text" name="IDNumbers[<?php echo $count; ?>]" value="<?php echo $ID; ?>" readonly></p>

    <input type="radio" name="approved[<?php echo $count; ?>]" value="Approve Review"> Approve Review<br>
    <input type="radio" name="approved[<?php echo $count; ?>]" value="Delete Review"> Delete Review<br>

  </div>
  <br>
  <?php } ?>
  <br>
  <br>
  <input type="submit" value="Submit">
</form>

-

<?php
    $CurrentID = "";
    if (isset($_GET['action'])) {
        $count2 = $counter;
        while ($count2 > "0"){
        $CurrentID = $_POST["IDNumbers[".$count2."]"];  
            if ($_POST["approved[".$count2."]"] = "Approve Review") {
                    $stmt = $pdo->prepare("UPDATE reviews SET Approved='1' WHERE (ID=?)");
                    $stmt->execute(array($CurrentID));
            } elseif ($_POST["approved[".$count2."]"] = "Delete Review") {
                    $stmt = $pdo->prepare("DELETE FROM reviews WHERE (ID=?)");
                    $stmt->execute(array($CurrentID));
            }
            $count2 = --$count2;
        }
        echo "<h2> Successful!</h2>";
    }
?>

此外还有其他一些代码，看起来按钮此刻什么都不做，我真的不太清楚为什么。我是PHP的新手，所以请轻松一下：）

如果有人可以通过其他方式看到这会出错，请告诉我，因为按钮无法正常工作，我还无法测试它。