Question

我已经在haskell中编写了一些代码，我刚刚遇到了上面的错误。我已经在这里寻找答案了，但找不到解决我问题的答案。

makeCtordecls :: RandomGen g => String -> RandomState g [Ctordecl]
makeCtordecls tp = do
  rng <- (randomRS (5 :: Int, 7 :: Int)
  let listOfCtordecl = replicateCountM rng (makeCtordecl (tp))
  return listOfCtordecl

replicateCountM :: (Applicative m) => Int -> (Int -> m a) -> m [a]
replicateCountM cnt0 f =
    loop cnt0
  where
    loop cnt
        | cnt <= 0  = pure []
        | otherwise = liftA2 (:) (f cnt) (loop (cnt - 1))

它说它无法解析＆＃34;让listOfCtordecl ....＆＃34;

Answer 1

你忘了关闭这条线上的人：

rng <- (randomRS (5 :: Int, 7 :: Int)

应该是：

rng <- (randomRS (5 :: Int, 7 :: Int))

Haskell的解析错误（可能是错误的缩进或括号不匹配）

1 个答案: