Question

我试图用构造函数声明类，但是似乎与该语法冲突并声明类成员。

有关这些如何结合在一起的任何建议吗？

class Person (aName:String) {
    var name : String
        get() = this.name
        set(myName) {this.name = myName}

    init {
        this.name = aName
    }
}

Answer 1

您可以通过set(myName) {this.name = myName}在设置器中使用setter。这是一个递归调用，而不是你应该做的。而是像这样使用field accessor：

name: String? = null
  set(myName) {
     field = myName
  }

但实际上，你甚至不需要这个。您可以在主构造函数中声明name应该是您的类的属性：

class Person(var name: String)

Answer 2

你不需要任何这些。您只需在构造函数中将Traceback (most recent call last): File "/tmp/env/lib/python2.7/site-packages/gunicorn/arbiter.py", line 578, in spawn_worker worker.init_process() File "/tmp/env/lib/python2.7/site-packages/gunicorn/workers/base.py", line 126, in init_process self.load_wsgi() File "/tmp/env/lib/python2.7/site-packages/gunicorn/workers/base.py", line 135, in load_wsgi self.wsgi = self.app.wsgi() File "/tmp/env/lib/python2.7/site-packages/gunicorn/app/base.py", line 67, in wsgi self.callable = self.load() File "/tmp/env/lib/python2.7/site-packages/gunicorn/app/wsgiapp.py", line 65, in load return self.load_wsgiapp() File "/tmp/env/lib/python2.7/site-packages/gunicorn/app/wsgiapp.py", line 52, in load_wsgiapp return util.import_app(self.app_uri) File "/tmp/env/lib/python2.7/site-packages/gunicorn/util.py", line 352, in import_app __import__(module) ImportError: Import by filename is not supported.定义为name，Kotlin就会将其作为属性公开。

var

Answer 3

只是为了添加其他人所说的内容，如果你想将aName作为一个单独的构造函数参数，这里有一个更好的语法：

class Person (aName:String) {
    var name = aName
}

类构造函数和成员变量（字段）

3 个答案: