from PIL import ImageGrab
pil_img=ImageGrab.grab([0,0,1000,1000])
答案 0 :(得分:2)
使用pil_img.getpixel((x, y))
或pil_img[x, y]
。
答案 1 :(得分:1)
如果你不在所有像素上自行编写循环,那就快得多。
import os.path
from collections import Counter
from PIL import Image
path_to_file = os.path.join('..', '..', 'img', '9BLW9.jpg')
# Count the number of occurrences per pixel value for the entire image
img = Image.open(path_to_file)
pixels = img.getdata()
print(Counter(pixels))
# Count the number of occurrences per pixel value for a subimage in the image
img = img.crop((100, 100, 200, 200))
pixels = img.getdata()
print(Counter(pixels))
结果:
Counter({(248, 8, 9): 1002251, (0, 0, 0): 735408, (248, 8, 11): 8700, (245, 9, 9): 7200, ...)
Counter({(0, 0, 0): 5992, (248, 8, 9): 1639, (3, 0, 0): 33, (0, 6, 0): 23, ...)
您有两个以上像素值的事实是由于JPG伪影造成的。您可以编写一些自定义逻辑来查看像素是否更像是黑色或红色,并将它们视为那些。