Question

我已经在xamarin.forms中创建了简单的登录页面，我有这些登录的API，而在postman运行时获取输出，但是从模拟器登录时，我收到以下错误。

{StatusCode：404，ReasonPhrase：＆＃39; Not Found＆＃39;，Version：1.1，Content：System.Net.Http.StreamContent，Headers： { 缓存控制：私有服务器：Microsoft-IIS / 8.0 X-AspNet-Version：4.0.30319 X-Powered-By：ASP.NET Set-Cookie：ARRAffinity = 639506ba4afdd530b4429c0d57e89977accb4b666a1e17dbe3fcc5c1fce369d5; Path = /; HttpOnly; Domain = snovahub.azurewebsites.net 日期：2017年9月13日星期三13:23:00 GMT 内容长度：3485 内容类型：text / html;字符集= utf-8的 }}

我的Api方法如下：

#region Get results from api
    public static async Task<T> GetResultFromApi<T>(string serviceUrl,bool isTrue=true)
    {
        try
        {              
            GetConnection();

            var response = await _httpClient.GetAsync(new Uri(SnovaHubApiUrls.SnovaHubWebUrl + serviceUrl));

            var stringAsync = await response.Content.ReadAsStringAsync();

            if (response.IsSuccessStatusCode)
            {
                var responseJson = stringAsync;

                return JsonConvert.DeserializeObject<T>(responseJson);
            }

            LoggingManager.Error("Received error response: " + stringAsync);
            return default(T);
        }
        catch (Exception exception)
        {
            LoggingManager.Error(exception);
            return default(T);
        }
    }
#endregion

Answer 1

问题是您正在设置HttpClient.BaseAddress，然后在调用HttpClient.GetAsync()时传入完整的网址。你需要选择其中一个。所以：

选项1：

private static void GetConnection() {
    if (_httpClient == null) {
         _httpClient = new HttpClient { BaseAddress = new Uri(SnovaHubApiUrls.SnovaHubWebUrl) }; //You MUST place a / (slash) at the end of your BaseAddress ("http://something.com/api/" for example)
    }
}

然后在您的GetResultFromApi()方法中：

...

var response = await _httpClient.GetAsync(serviceUrl); //You MUST NOT place a slash at the beginning of 'serviceUrl' when using BaseAddress

选项2：

private static void GetConnection() {
    if (_httpClient == null) {
         _httpClient = new HttpClient(); //Removed BaseAddress
    }
}

然后在您的GetResultFromApi()方法中：

...

var response = await _httpClient.GetAsync(new Uri(SnovaHubApiUrls.SnovaHubWebUrl + serviceUrl)); //Passing full URL

从模拟器

1 个答案: